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Montano1993 [528]
3 years ago
7

Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what

is its correct name? C1B4 (monocarbon tetrabromide) C1Br4 (monocarbon tetrabromide) CB4 (carbon tetrabromide) CBr4 (carbon tetrabromide)
Physics
2 answers:
Alik [6]3 years ago
7 0

Answer: CBr_4 : carbon tetrabromide

Explanation:

CBr_4 is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for CBr_4 is carbon tetrabromide.

cupoosta [38]3 years ago
3 0

Answer:

Carbon tetrabromide ~ CBr4

Chlorine monofluoride~ ClF

Explanation:

EDGU 2021

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<u>Answer:</u>

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Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

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3 years ago
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3 years ago
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1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].

2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].

3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].

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