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Sholpan [36]
3 years ago
9

Thinner in the center that at the edges; virtual image smaller.

Chemistry
2 answers:
givi [52]3 years ago
8 0

Answer:

The correct answer is concave lenses.

Explanation:

A concave lens refers to a lens, which exhibits at least one surface that bends inwardly. It is a diverging lens, which signifies that it disperses out the light rays that have been refracted via it. A concave lens is thinner at its midpoint in comparison to its edges and has an application in correcting short-sightedness.  

The formation of an image by a concave lens is virtual, which signifies that it will seem to be farther away than it actually is, and thus, smaller in comparison to the object itself.  

ipn [44]3 years ago
3 0
<h3><u>Answer</u>;</h3>

Concave Lenses

<h3><u>Explanation</u>;</h3>
  • A concave lens is thin in the middle and thick at the edges, such that it seems to cave inwards. It spreads light rays apart producing an image smaller than the actual object.
  • <em><u>Images formed by a concave lens are virtual, upright, reduced in size and located on the same side of the lens as the object. Diverging lenses or concave lens always produce images that share these characteristics. The location of the object does not affect the characteristics of the image. </u></em>
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Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,
gayaneshka [121]

Answer:

B > D > C > A

Explanation:

For the first law of the thermodynamics, the total energy variation in a process is:

ΔU = Q - W

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A. If the surroundings get colder, the system is absorbing heat, so Q>0, and the system decreases in volume so W < 0 :

ΔU = +Q - (-W) = +Q + W (absorbs a higher energy)

B. If the surroundings ger hotter, the system is losing heat, so Q<0, and the system expands, so W>0:

ΔU = -Q -W (loses higher energy)

C. Surroundings get hotter, Q<0, and the system decreases in volume, W<0

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D. Surroundings get hotter, Q<0, and the system is not changing in volume, W = 0.

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For the most released (more negative) for the most absorbed (most positive):

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3 0
3 years ago
2C2H6 + 7O2 ------&gt; 4CO2 + 6H2O
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We convert the masses of our reactants to moles and use the stoichiometric coefficients to determine which one of our reactants will be limiting.

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(10 g O2)(31.999 g/mol) = 0.3125 mol O2.

Every 2 moles of C2H6 react with 7 moles of O2. So the number of moles of O2 needed to react completely with 0.3326 mol C2H6 would be (0.3326)(7/2) = 1.164 mol O2. That is far more than the number of moles of O2 that we are given: 0.3125 moles. Thus, O2 is our limiting reactant.

Since O2 is the limiting reactant, its quantity will determine how much of each product is formed. We are asked to find the number of grams (the mass) of H2O produced. The molar ratio between H2O and O2 per the balanced equation is 6:7. That is, for every 6 moles of H2O that is produced, 7 moles of O2 is used up (intuitively, then, the number of moles of H2O produced should be less than the number of moles of O2 consumed).

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Given 10 grams of C2H6 and 10 grams of O2, 4.826 g of H2O are produced.

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I hope this helps.  Let me know in the comments if anything is unclear.
5 0
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