Question

A car on a roller coaster starts at zero speed at an elevation above the ground of 26 m. It coasts down a slope, and then climbs a hill. The top of the hill is at an elevation of 16 m. What is the speed of the car at the top of the hill

Answer 1

Answer:

14 m/s

Explanation:

The velocity u at the ground from an elevation of 26 m is given by

$u=\sqrt{2gh} =\sqrt{2\times9.8\times26} \text{ m/s}$

Now, the speed of the car v at the top of the hill , which is at an elevation of 16 m can be calculated by

$v^2 =u^2-2gh= 2\times9.8\times26-2\times9.8\times16\\=2\times9.8\times10\\=196\\=14 \text{ m/s}$