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masha68 [24]
3 years ago
7

Please help me-. it’s part of my major grade.

Physics
2 answers:
stich3 [128]3 years ago
7 0
It will continue to not move- if you leave an object alone it’s not going to move unless something happens to it - I.e an outside force.

Let me know if you have any questions
Serga [27]3 years ago
6 0

Answer:

c

Explanation:

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If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is
Brilliant_brown [7]

Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative             Precipitation                                

                        Low                Normal                 High

Do nothing    -100                       100                    300

Expand           350                       500                   200

Build new       750                       300                    0

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is EVPI (Expected value of Perfect Information)?

A. $140,000

B. $170,000

C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

The expected long run profits are  for

                        Low                Normal                 High

Do nothing    -100*0.3                100*0.2                   300*0.5 = 140

Expand           350*0.3                500*0.2                  200*0.5 = 305

Build new       750*0.3                300*0.2                  0*0.5    = 285

Therefore the expected long run profits are

$140,000

$305,000

$285,000

Based on his selected option being either to build new or to expand, the most profitable option is to expand

=$305,000

EVPI = EPPI-EMV =$170,000

7 0
3 years ago
A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Anastaziya [24]

Answer:

The gauge pressure is  P_g  =  2058 \ P_a

Explanation:

From the question we are told that

       The height of the water contained is  h_w  =  30 \ cm  =  0.3 \ m

        The height of liquid in the cylinder is  h_t  =  40 \ cm  = 0.4 \ m

       

At the bottom of the cylinder the gauge pressure is  mathematically represented as

        P_g  =  P_w + P_o

Where  P_w is the pressure of water which is mathematically represented as

      P_w  =  \rho_w  *  g * h_w

Now  \rho_w is the density of water with a constant values of  \rho_w  = 1000 \ kg /m^3

   substituting values

      P_w  = 1000 *  9.8 *  0.3

     P_w  =  2940 \  Pa

While P_o is the pressure of oil which is mathematically represented as

          P_o  =  \rho_o *  g *  (h_t -h_w )

Where \rho _o is the density of oil with a constant value

         \rho _o  = 900 \ kg / m^3

substituting values

       P_o  =  900 *  9.8 * (0.4 - 0.3)

       P_o  =  882 \ Pa

Therefore

      P_g  =  2940 - 882

      P_g  =  2058 \ P_a

6 0
3 years ago
A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the
BartSMP [9]

Answer:

r=1.14m

Explanation:

\theta is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

F_m=F_c\\qvB=F_c(1)

F_c is the centripetal force and is defined as:

F_c=m\frac{v^2}{r}

Here v is the proton's speed and r is the radius of the circular motion. Replacing this in (1) and solving for r:

qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}

Recall that 1 J is equal to 6.242*10^{12}MeV, so:

4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J

We can calculate v from the kinetic energy of the proton:

K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}

Finally, we calculate the radius of the proton path:

r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m

8 0
3 years ago
If you exert a force of 100.0 N to lift a box a distance of 0.5 m, how much work do you do? 200 J 400 J 50 J 26 J
jeyben [28]
Work = force x distance
= 100N (force) x 0.5m (distance)
=  50J
4 0
3 years ago
As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which comp
faltersainse [42]

Answer:  The volume of gas expands because of the decrease in pressure as he tries to exit the water body, therefore he must take necessary precaution.

Explanation:

Using Boyle's law which states that the  the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature

ie P1VI=P2V2

A diver absorbs compressed nitrogen gas when  he dives into the water body, As he ascends  out of the water body having less pressure, the volume of nitrogen gas which he absorbs will tend to expand following  Boyle's Law.  Therefore a scuba driver should not rises quickly but slowly  to the surface or else the  expanding nitrogen gas can cause tiny bubbles in his blood and tissue to form together with joints pains and eventually  cause decompression sickness needing medical attention.

5 0
3 years ago
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