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masha68 [24]
3 years ago
7

Please help me-. it’s part of my major grade.

Physics
2 answers:
stich3 [128]3 years ago
7 0
It will continue to not move- if you leave an object alone it’s not going to move unless something happens to it - I.e an outside force.

Let me know if you have any questions
Serga [27]3 years ago
6 0

Answer:

c

Explanation:

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The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC
enyata [817]

Answer:

The y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

Explanation:

<u>Given:</u>

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where, \hat i,\ \hat j are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.

Thus, the y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

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3 years ago
A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial s
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<span>(1)   </span>Through the Second Law of motion, the equation  for Force is:

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Where m is mass and a is acceleration (deceleration)

 

<span>(2)   </span>Distance is calculated through the equation,

                             D = Vi^2 / 2a

Where Vi is initial velocity

<span>(3)   </span>Work is calculated through the equation,

                          W = F x D

 

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<span>(3)   </span>  W = (170 N)(9.25 m) = 1572.5 J

 

Part B:

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<span>(2)   </span>D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

<span>(3)   </span><span> W = (340 N)(4.625 m) = 1572.5 J</span>

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3 years ago
It is important to use the correct drying tempture because it prevents shrinkage and will not damage the garment.
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kbegtrf3g4ef j3kq4ef 3w4beysrf2w4er8f6ywgbaebf7v2wy4egdwa4i6e5

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