Answer:
a) 
b)
degrees and on this case to the South of the East.
c)
d) 
So it would be 250 to the South
Explanation:
Part a
For this case the figure attached shows the illustration for the problem.
We know that
represent the velocity of the river to the south.
We have the velocity of the motorboard relative to the water and on this case is 
And we want to find the velocity of the motord board relative to the Earth 
And we can find this velocity from the Pythagorean Theorem.

Part b
We can find the direction with the following formula:
degrees and on this case to the South of the East.
Part c
For this case we can use the following definition

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

Part d
For this case we can use the same definition but now using the y compnent we have:

And replacing we got:

So it would be 250 to the South
Sry,I only know the answer of q2
Chlorine is a non metal because it is bad conductor of heat and sodium is a metal because it is good conductor of heat.
The 3 ways in which metal is different from non metal are given below:
1)metal are good conductor of heat but nonmetal are bad conductor of heat.
2)metals are malleable but non metal aren't malleable.
3)metals are generally ductile but non metal aren't ductile.
Hope it will helpyou!
Answer:
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Answer:
(a) F = 15.12 N
(b) a = 30.24 m/s²
(c) To Left
Explanation:
(a)
The magnitude of the spring force is given by Hooke's Law as follows:
F = kx
where,
F = Spring Force = ?
k = Spring Constant = 126 N/m
x = Displacement = A = 0.12 m
Therefore,
F = (126 N/m)(0.12 m)
<u>F = 15.12 N</u>
(b)
The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:
F = ma
where,
F = Spring Force = 15.12 N
m = mass of block = 0.5 kg
a = magnitude of acceleration = ?
15.12 N = 0.5 kg (a)
a = 15.12 N/0.5 kg
<u>a = 30.24 m/s²</u>
<u></u>
(c)
Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be <u>to left.</u>