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bogdanovich [222]
2 years ago
14

A football player who weighs 550 N stands indoors wearing her football boots. The boot’s

Physics
1 answer:
EleoNora [17]2 years ago
3 0

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

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A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on
Natasha2012 [34]

Answer:

\huge\boxed{\sf F = 0.28\ N}

Explanation:

<h3>Given Data:</h3>

Mass = m = 68 kg

Velocity = v = 30 m/s

Time = 2 hours = 2 × 60 × 60 = 7200 s

<h3>Required:</h3>

Force = F = ?

<h3>Formula to be used:</h3>

\displaystyle F = \frac{mv}{t}

<h3>Solution:</h3>

\displaystyle F = \frac{(68)(30)}{7200} \\\\F = \frac{2040}{7200} \\\\F = 0.28 N\\\\\rule[225]{225}{2}

7 0
1 year ago
A lemming running 2.22m/s runs off a horizontal cliff. It lands in the water 7.45m from the base of the cliff. How much time was
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6 0
3 years ago
What observations can the geologist make by working outdoors instead of in a lab?
vredina [299]

Answer:

Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.

<u>Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows:</u>

  • Understanding and exploring the earth's surface closely using geophysical tools.
  • Collecting samples by own and make some interpretations at the same time.
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8 0
3 years ago
What element has 3 valence electrons and 4 energy levels​
Tems11 [23]
Gallium is the answer
6 0
3 years ago
An object is dropped from rest from a 70.6 m tower. Air resistance is negligible. After 0.32 seconds, what is magnitude and dire
dem82 [27]

Answer:

<em>1,378.9ms²</em>

Explanation:

Given the following

Distance S = 70.6m

Time t = 0.32secs

Initial velocity = 0m/s

Required

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Using the equation of motion

S = ut+1/2at²

Substitute

70.6 = 0+1/2a(0.32)²

70.6 = 0.0512a

a = 70.6/0.0512

a = 1,378.9

<em>Hence the acceleration is 1,378.9ms²</em>

7 0
2 years ago
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