The Moon s escape speed will be smaller than Earth's.
The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.
The formula of escape speed is
where
v is escape velocity
G is universal gravitational constant
M is mass of the body to be escaped from
r is distance from the center of the mass
we can say that,
Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.
we know that,
The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.
since, v ∝ g
The Moon s escape speed will be smaller than Earth's.
Learn more about escape speed here:
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Answer:
a. 8p
Explanation:
We are given that
Radius of hollow sphere , R1=R
Density of hollow sphere=![\rho](https://tex.z-dn.net/?f=%5Crho)
After compress
Radius of hollow sphere, R2=R/2
We have to find density of the compressed sphere.
We know that
![Density=\frac{mass}{volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7Bmass%7D%7Bvolume%7D)
![Mass=Density\times volume=Constant](https://tex.z-dn.net/?f=Mass%3DDensity%5Ctimes%20volume%3DConstant)
Therefore,![\rho_1 V_1=\rho_2V_2](https://tex.z-dn.net/?f=%5Crho_1%20V_1%3D%5Crho_2V_2)
Volume of sphere=![\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
Using the formula
![\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3](https://tex.z-dn.net/?f=%5Crho%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20R%5E3%3D%5Crho_2%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%28R%2F2%29%5E3)
![\rho R^3=\rho_2\times \frac{R^3}{8}](https://tex.z-dn.net/?f=%5Crho%20R%5E3%3D%5Crho_2%5Ctimes%20%5Cfrac%7BR%5E3%7D%7B8%7D)
![\rho_2=8\rho](https://tex.z-dn.net/?f=%5Crho_2%3D8%5Crho)
Hence, the density of the compressed sphere=![8\rho](https://tex.z-dn.net/?f=8%5Crho)
Option a is correct.
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