Question

Two conductors having net charges of +16.0 HC and -16.0 HC have a potential difference of 16.0 V between them. (a) Determine the capacitance of the system (b) What is the potential difference between the two conductors if the charges on each are increased to +256.0 C and-256.0 uC

Answer 1

Answer:

(a) Capacitance is $1\mu C$

(b) Potential difference is 256 V

Solution:

As per the question:

Charges on the two conductors, q is  $+ 16\muC$ and $- 16\muC$

The potential difference between the charges, V = 16.0 V

Now,

(a) The capacitance of the system is given by:

q = CV

$C = \frac{q}{V} = \frac{16\times 10^{- 6}}{16} = 1\mu F$

(Since, $1\mu C = 10^{- 6} C$)

Now,

(b) When the charge, 'q' is increased to $+ 256\mu C$ and $- 256\mu C$

q = CV

$V = \frac{q}{C} = \frac{256\times 10^{- 6}}{1\times 10^{- 6}} = 256\ V$