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Free_Kalibri [48]

4 years ago

7

Molar mass is measured in units of

1 answer:

joja [24]4 years ago

7 0

The SI unit for molar mass is grams/mole.

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A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T

Dennis_Churaev [7]

Answer:

The value of x is $x = 0.1955\ m$

The value of the velocity at the top is $v_{top} = 2.25 \ m/s$

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

The mass of the block is $m_b = 0.490kg$

The distance of compression is $x$

The force constant is $k = 450 N/m$

The radius of the circular track is $R =1.00m$

The speed at the bottom of the track is $v_A = 13.4 \ m/s$

The frictional force experienced is $F_f = 7.00 \ N$

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy of the block . So,

$PE \ of \ spring = KE \ of \ block$

mathematically i.e

$\frac{1}{2}k x^2 = \frac{1}{2} m_bv^2_A$

$0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2$

Making x the subject of the formula

$x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }$

$= 0.1955\ m$

The average workdone by friction is $W_f = F_f * \pi$

Here $\pi is \ the\ net\ displacement$

$W_f = 7 * 3.142$

$= 21.99 J$

The kinetic energy at the bottom is

$KE = \frac{1}{2} * 0.490 * 13.4^2$

$= 43.99 \ N$

The potential energy gained at the top of the circle is

$PE = m_bgh$

Here h is the height which is equal to d(diameter) = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity $= 9.8m/s^2$

Now substituting values

$PE = 0.490 * 9.8 *2$

$=9.604 J$

Since energy is can not be created nor destroyed but transformed according to first law of thermodynamics

$KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}$

$43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]$

$12.369= [2.45* v_{top} ^2]$

$v_{top} =\sqrt{\frac{12.369}{2.45} }$

$= 2.25 \ m/s$

8 0

3 years ago

What is the total number of atoms in the following formula? CaBr2 4 3 2 1

ololo11 [35]

Your answer is 3 ( 1 calcium atom and 2 bromine atoms)

8 0

3 years ago

Do action and reaction cancel each other out?

galben [10]

Answer:

Action and reaction forces don't cancel each other out because they act on separate objects. ... Action and reaction forces are always equal in magnitude, so it's not possible to exert more force on an object than it can exert back.

Explanation:

8 0

3 years ago

A horizontal force pushes a 26 kg sled along a driveway for a distance of 36 m. If the coefficient of sliding friction is 0.2, w

SVETLANKA909090 [29]

Answer:1834.56 joules

Explanation:

Distance=36m

Coefficient of friction=0.2

Mass=26kg

Acceleration due to gravity=9.8m/s^2

Reaction=mass x acceleration due to gravity

Reaction=26 x 9.8

Reaction=254.8N

Coefficient of friction=frictional force ➗ reaction

0.2=frictional force ➗ 254.8

Frictional force=0.2 x 254.8

Frictional force=50.96N

work=friction force x distance

Work=50.96 x 36

Work=1834.56

Work=1834.56 joules

8 0

4 years ago

A 2 kg car accelerated from 10 m's to 20 m/s using a force of 3000N. How quickly did it

elena-14-01-66 [18.8K]

Answer:

the car accelerates in

$\frac{1}{150} \: or \: 0.006 \: second$

Explanation:

here's the solution : -

we know,

=》

$force = mass \times acceleration$

=》

$acceleration = \frac{force}{mass}$

=》

$a = \frac{3000}{2}$

=》

$a = 1500$

so, acceleration = 1500 m/s^2

now,

=》

$a = \frac{v - u}{t}$

here, a = acceleration, v = final velocity,

u = initial velocity, t = time taken.

So,

=》

$1500 = \frac{20 - 10}{t}$

=》

$1500 = \frac{10}{t}$

=》

$t = \frac{10}{1500}$

=》

$t = 0.006 \: sec$

7 0

3 years ago