Answer:
Explanation:
Pressure due to fluid is directly proportional to the depth of fluid, density of the fluid and the value of acceleration due to gravity.
P = h d g
Where, h is the depth, d be the density and g be the acceleration due to gravity.
If we talk about teh atmospheric pressure, the density of air goes on decreasing as we go up and up. o we cannot say that it is directly depends only on the depth of air, it also depends on the changing density of air.
Answer:
The answer is the second option.
Explanation:
This is a higher temperature than Onnes's experiment, and it will allow for a broader use of superconductors.
Pressure is measured as force per unit area, which is the third option.
<h3>What is pressure?</h3>
Pressure is amount of force that is applied over a given area divided by the size of this area.
Pressure is calculated by multiplying the force applied on the object by the area covered.
Since force is measured in Newtons (N) and area is measured in m², the unit of pressure is Nm².
Therefore, pressure is measured as force per unit area.
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By calculation, the diameter of the wire is 2.8 * 10^-3 m.
<h3>How do we obtain the length?</h3>
The following data are given in the question;
Mass of the wire = 1.0 g or 1 * 10^-3 Kg
Resistance = 0.5 ohm
Resistivity of copper = 1.7 * 10^-8 ohm meter
Density of copper = 8.92 * 10^3 Kg/m^3
V = m/d
But v = Al
Al = m/d
A = m/ld
Resistance = ρl/A
= ρl/m/ld =
l^2 = Rm/ρd
l = √ Rm/ρd
l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3
l = 1.82 m
A = πr^2
Also;
A = m/ld
A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3
Area of the wire = 6.2 * 10^-5 m^2
r^2 = A/ π
r = √A/ π
r = √6.2 * 10^-5 m^2/3.142
r = 1.4 * 10^-3 m
Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m
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Missing parts;
Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?
Answer:
V = 50 volts
Explanation:
Given that,
Resistance, R = 10 ohms
Current, I = 5 A
We need to find the potential difference across the circuit. We know that,
V = IR
Put all the values,
V = 5 × 10
V = 50 volts
Hence, the potential difference is equal to 50 volts.