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gogolik [260]
3 years ago
7

A 2 kg car accelerated from 10 m's to 20 m/s using a force of 3000N. How quickly did it

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

the car accelerates in

\frac{1}{150}  \: or \: 0.006 \: second

Explanation:

here's the solution : -

we know,

=》

force = mass   \times acceleration

=》

acceleration =  \frac{force}{mass}

=》

a  =  \frac{3000}{2}

=》

a = 1500

so, acceleration = 1500 m/s^2

now,

=》

a =  \frac{v - u}{t}

here, a = acceleration, v = final velocity,

u = initial velocity, t = time taken.

So,

=》

1500 =  \frac{20 - 10}{t}

=》

1500 =  \frac{10}{t}

=》

t =  \frac{10}{1500}

=》

t = 0.006 \: sec

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Answer:

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3742514.97005

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F_d=\frac{1}{2}\rho CAv^2\\\Rightarrow F_d=\frac{1}{2}\times 1000 \times 0.09(\pi 0.25^2)7.5^2\\\Rightarrow F_d=497.00977\ N

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at 20°C

\mu = Dynamic viscosity = 1.002\times 10^{-3}\ Pas

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A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el
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Answer:

7.2\cdot 10^{-19} J

Explanation:

The change in electrical potential energy of a charged particle moving through a potential difference is given by

\Delta U = q \Delta V

where

q is the magnitude of the charge of the particle

\Delta V is the potential difference

In this problem:

- the charge of the particle is 3.00 elementary charges, so

q=3e=3\cdot 1.6\cdot 10^{-19} J=4.8\cdot 10^{-19}J

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So, the change in electrical potential energy is

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