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gogolik [260]
3 years ago
7

A 2 kg car accelerated from 10 m's to 20 m/s using a force of 3000N. How quickly did it

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

the car accelerates in

\frac{1}{150}  \: or \: 0.006 \: second

Explanation:

here's the solution : -

we know,

=》

force = mass   \times acceleration

=》

acceleration =  \frac{force}{mass}

=》

a  =  \frac{3000}{2}

=》

a = 1500

so, acceleration = 1500 m/s^2

now,

=》

a =  \frac{v - u}{t}

here, a = acceleration, v = final velocity,

u = initial velocity, t = time taken.

So,

=》

1500 =  \frac{20 - 10}{t}

=》

1500 =  \frac{10}{t}

=》

t =  \frac{10}{1500}

=》

t = 0.006 \: sec

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H = MCΔT

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5 0
3 years ago
Read 2 more answers
If an arrow is shot upward on the moon with a velocity of 58 m/s, its height (in meters) after t seconds is given by H = 58t − 0
Alex73 [517]

Answer:

a) v = 54.7m/s

b) v = (58 - 1.66a) m/s

c) t = 69.9 s

d) v = -58.0 m/s

Explanation:

Given;

The height equation of the arrow;

H = 58t - 0.83t^2

(a) Find the velocity of the arrow after two seconds. m/s;

The velocity of the arrow v can be given as dH/dt, the change in height per unit time.

v = dH/dt = 58 - 2(0.83t) ......1

At t = 2 seconds

v = dH/dt = 58 - 2(0.83×2)

v = 54.7m/s

(b) Find the velocity of the arrow when t = a. m/s

Substituting t = a into equation 1

v = 58 - 2(0.83×a)

v = (58 - 1.66a) m/s

(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s

the time when H = 0

Substituting H = 0, we have;

H = 58t - 0.83t^2 = 0

0.83t^2 = 58t

0.83t = 58

t = 58/0.83

t = 69.9 s

(d) With what velocity will the arrow hit the surface? m/s

from equation 1;

v = dH/dt = 58 - 2(0.83t)

Substituting t = 69.9s

v = 58 - 2(0.83×69.9)

v = -58.0 m/s

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3 years ago
The gravitational force between two objects depends on the masses and what factor between them?
Charra [1.4K]
It depends on mass and distance.  
8 0
3 years ago
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