Answer:
a. 2.959kgm/s
b. 7.63kgm/s
Explanation:
We were given Mass= 0.25kg
Velocity = 13m/s
Angle = 46°
a) Along the x axis we have =
0- 0.25(13)cos(46°) = (- 2.26)i kgm/s
Along the y axis we have =
-0.25(20) +0.25(13)sin(46°) = (-1.91)j kgm/s
Magnitude of change in momentum
=√ i²+ j²
= √ (-2.26)²+ ( -1.91)²
= √8.7557
= 2.959 kgm/s
b.
Along the x axis
-0.25(20) - 0.25(13)cos(46°) = (-7.26)i kgm/s
Along the y axis
0 + 0.25(13)sin(46°) = (-2.34)j kgm/s
Magnitude of change in momentum
= √ i²+ j²
= √( -7.26)² + (-2.34)²
= √58.1832
= 7.63kgm/s
Explanation:
This process is called Bonding and it is done to provide low resistance path to ground.
"Bonding — a low impedance direction achieved by permanently connecting all non-current-carrying metal parts to maintain electrical stability and to be able to conduct any current that is likely to be put on it safely.
Answer:
Energy production requires the setting up of a complete interconnected chain from generation of energy from the root source of the energy to the storage of the generated energy and the eventual utilization of the energy when required
Solar energy, indirectly, continues to be the main source of energy, however, the direct use of solar energy to power the systems we use in our everyday life, require the development of technologies, such as high efficiency solar cells, means of energy storage, and compatible efficient energy usage which are industrial areas that are seeing good progress but in which the current developed equipment are expensive to produce, and due to their efficiency, are undergoing further research and development
Therefore, due to the continuous increasing improvement in solar technology which can observed, the use of the produced energy through solar is evolving, and therefore, will continue to play a continuously increasing but lower role compared to other sources of energy which have been developed to satisfactory level that can drive an industry, considering the financial investment involved
Explanation:
The height is zero.
That means whatever place is your reference for height measurement,
the object is lying right there at that height.
Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q