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Mashutka [201]
2 years ago
8

3. What is the density of a substance that weighs 39.1 g and is 56.0 mL? (Density = g/mL)

Physics
1 answer:
Alex Ar [27]2 years ago
3 0
.689214 g/ml.
Truthfully this is an easy calculation you should have been able to do but I’ll help you out
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An electron in a TV picture tube is accelerated through a potential difference of 10 kV before it hits the screen. What is the k
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Answer:

10,000 eV

Explanation:

According to the law of conservation of energy, the kinetic energy gained by the electron is equal to its change in electric potential energy:

K=\Delta U=q \Delta V

where:

K is the kinetic energy of the electron

q=1 e is the magnitude of the charge of the electron

\Delta V is the potential difference through which the electron has been accelerated

For this electron in the TV, we have

\Delta V=10 kV=10000 V

Therefore, the kinetic energy of the electron in electronvolts is

K=(1 e)(10000 V)=10000 eV

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3 years ago
A 300N box on a 43 degree angle.
Ksenya-84 [330]

Answer:is this a question??? I’m so confused

Explanation:

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How far should pencil held from a convex mirror of radius 80 cm to form an image one-half the size of the pencil?
prisoha [69]

Answer:

10.0

Explanation:

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2 years ago
An incompressible fluid flows at .252 m/s through a 44 diameter (circular cross section) pipe. The pipe widens to a square cross
Serggg [28]

ANSWER:

The easiest way to get a fairly accurate measure of your water flow rate is to time yourself filling up a bucket. So for example if you fill up a 10 litre bucket in 1.5 minutes, then your flow rate will be: 10/1.5 = 6.66 Litres per minute.

7 0
2 years ago
A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

7 0
3 years ago
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