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3 years ago

What is projectile motion is caused by?

2 answers:

8 0

A projectile is any object that is thrown, dropped or otherwise laughed into the air.
1) If it is dropped - it's motion is caused by just gravitation force
2) if it is thrown - it's motion is caused by gravitation force + force you applied to though it upwards

kirza4 [7]3 years ago

6 0

The answer is

The downward force of gravity and an initial forward velocity

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Based on the Law of Conservation of Matter, what number should be placed in the box to balance the chemical equation below?

Rashid [163]

Answer:

Explanation:

Step 1: RxN

4Al + 3O₂ → Al₂O₃

Step 2: Balance RxN

We have 4 Al's and 6 O₂'s on the reactant side.

We need the same number of Al's and O₂'s on the product side.

4Al + 3O₂ → 2Al₂O₃

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3 years ago

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Which of the following lists Earth's compositional layers in order of increasing density?

WITCHER [35]

The lists that arranges the Earth's compositional layers in order of increasing density is CRUST, MANTLE AND THEN CORE. The core is considered as the most dense and the lithosphere, which makes the outermost core, is considered as having the least density. Hope that this answer helps.

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3 years ago

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the circumference of Earth's orbit is 938 million kilometres how fast does earth travel in km/h in one year

allsm [11]

Answer:

about 940 million km each year

Explanation:

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3 years ago

The certain forest moon travels in an approximately circular orbit of radius

Alinara [238K]

Answer:

Mass of Exoplanet = 0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

$speed = v = \frac{Circumference}{time}\\$

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

$v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s$

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

$Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}$

<u>Mass of Exoplanet = 0.58 kg</u>

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3 years ago

When electric current is flowing in a circuit, if the voltage applied to the circuit is increased, the

maw [93]

<span>a. current will increase. </span>

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3 years ago

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