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Cloud [144]
3 years ago
10

What is the purpose of this material in the nucleus?*

Chemistry
1 answer:
iogann1982 [59]3 years ago
3 0

Answer: DNA makes protein molecules to help with almost every cellular process.

i think?

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What is the concentration (in M) of a sample of the unknown dye with an absorbance of 0.25 at 542 nm?
Sladkaya [172]

Answer:

see explanation below

Explanation:

Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

Where:

ε: molar absortivity

l: distance of the light in solution

c: concentration of solution

However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.

the equation according to the plot is:

A = 15200c - 0.018

So solving for C for an absorbance of 0.25 is:

0.25 = 15200c - 0.018

0.25 + 0.018 = 15200c

0.268 = 15200c

c = 0.268/15200

c = 1.76x10⁻⁵ M

5 0
3 years ago
Express the following quantity in scientific notation. The answer needs to have the correct number of significant figures. 21,30
melisa1 [442]
2.13 x 10 E 7 i believe this is correct
4 0
4 years ago
Read 2 more answers
Mass = 386g volume= 30cm3
dezoksy [38]
Can you be more specific, I think the answer is 7.1506
7 0
3 years ago
Read 2 more answers
How many atoms are in NH4Cl.
RSB [31]

Answer:

there are 6

Explanation:

3 0
3 years ago
Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentratio
grigory [225]

Answer : The equilibrium concentration of CH_3OH will be, (C) 2.82\times 10^{-1}

Explanation :  Given,

Equilibrium constant = 14.5

Concentration of CO at equilibrium = 0.15 M

Concentration of H_2 at equilibrium = 0.36 M

The balanced equilibrium reaction is,

CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[CH_3OH]}{[CO][H_2]^2}

Now put all the values in this expression, we get:

14.5=\frac{[CH_3OH]}{(0.15)\times (0.36)^2}

[CH_3OH]=2.82\times 10^{-1}M

Therefore, the equilibrium concentration of CH_3OH will be, (C) 2.82\times 10^{-1}

5 0
3 years ago
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