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Bas_tet [7]
3 years ago
12

I need help with this question its not hard at all im just not sure

Chemistry
1 answer:
Lena [83]3 years ago
7 0

Answer:

It is the third one, 2 atoms of Aluminum and 3 atoms of Oxygen

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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 \frac{cal}{gC}.

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

  • Q is the heat exchanged by a body of mass m.
  • C is the specific heat substance.
  • ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

  • Mass of metal = 50 g
  • Initial temperature of metal= 45 °C
  • Final temperature of metal= 11.08 ºC
  • Specific heat of metal= ?

For water:

  • Mass of water = 250 g
  • Initial temperature of water= 10 ºC
  • Final temperature of water= 11.08 ºC
  • Specific heat of water = 1.035 \frac{cal}{gC}

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater=  1.035 \frac{cal}{gC} × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 \frac{cal}{gC} × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 \frac{cal}{gC} × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= \frac{279.45 cal}{1696 gC}

<u><em>Specific heat of metal= 0.165 </em></u>\frac{cal}{gC}

Finally, the specific heat of metal is 0.165 \frac{cal}{gC}.

Learn more about calorimetry:

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brainly.com/question/14057615

brainly.com/question/24988785

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7 0
1 year ago
Solid a is a very hard electrical insulator in solid as well as in molten state and melts at extremely high temperature. What ty
devlian [24]

This is covalent network type of solid.

For example, silicon dioxide (SiO₂) is covalent network solid with covalent bonding.

Covalent network solid is a chemical compound (or element) in which the atoms are bonded by covalent bonds in a continuous network extending throughout the material.

Silicon(IV) oxide has continuous three-dimensional network of SiO₂ units and diamond has sp3 hybridization.

This solids do not have free electrons so they are good insulators.

They have strong covalent bonds, so they melt at extremely high temperature.

Other examples are quartz, diamond, and silicon carbide.

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1 year ago
Which atom has the largest atomic radius
Greeley [361]
francium , in the Periodic table the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. making helium is the smallest element, and francium the largest.
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What is another name for a Grasshopper?
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Answer:

The scientific name of the grasshopper is Caelifera.

Explanation:

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2 years ago
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How many 5 MB mp3 files can be stored on a 1 GB flash drive?
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200files

Explanation:

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