Answer:
the answer to the qustion is 0.013089701 na
Explanation:
n/a
Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g
Answer:
3.01 x 103 J
Explanation:
To determine the average kinetic energy of a gas, it is necessary to use the equation, KE = 3/2 RT. The value of R, multiplied by the temperature, and multiplied by 3/2, can provide the average kinetic energy of the gas.
1mole contains 22.4Lmol^-1
xmole contains 8.943
cross-multiply
x=1×8.943/22.4
x=0.40mole
there it contains 0.40moles.
Answer:
C
Explanation:
3
Because you don't count the dots. You count how many colors there are. Which are Blue, Red, and Black.
Hope this helped!
