<span>Solar panels convert light energy from sunlight into electricity energy , Metalloid is most likely used in solar panels The answer is : </span> A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it. Metalloids are shiny,<span> semiconductive and they are brittle.</span>
<h2>Greetings!</h2>
To find this value, you need to remember the speed formula:
3 = 6 / 2
Speed = distance ÷ time
Rearrange to make distance the subject:
Distance = speed * time
Simply plug these values into this:
5.6 * 8.25 = 46.2
<h3>So the player will travel 46.2 metres!</h3>
<h2>Hope this helps!</h2>
Answer:
A meteor is B) an icy body with a long tail extending from it.
Explanation:
Meteors are very small dust particles that, when penetrating into the Earth's atmosphere, burn quickly by rubbing with the gases of the same. Some meteors, those with larger dimensions and appreciable weights, are brighter and can describe longer trajectories, showing longer.
In other words, the meteoroids, celestial bodies can vary in size between 100 micrometers up to 50 meters, they collide with the atmosphere of our planet and if the particles are of a small size, upon impact they enter combustion creating a flash, is what we know as meteor or shooting star. Therefore, the meteor is a luminous phenomenon that leaves behind a persistent trail.
So, <u><em>a meteor is B) an icy body with a long tail extending from it.</em></u>
Answer: 490N
Explanation:
Newton is the unit for force. Force = mass x acceleration
F=N m=50kg a=9.8 (earth's acceleration of gravity)
F=50X9.8
F≈490N
Answer:
B. 1700 Hz, 5100 Hz
Explanation:
Parameters given:
Length of ear canal = 5.2cm = 0.052 m
Speed of sound in warm air = 350 m/s
The ear canal is analogous to a tube that has one open end and one closed end. The frequency of standing wave modes in such a tube is given as:
f(m) = m * (v/4L)
Where m is an odd integer;
v = velocity
L = length of the tube
Hence, the two lowest frequencies at which a dog will have increased sensitivity are f(1) and f(3).
f(1) = 1 * [350/(4*0.052)]
f(1) = 1682.69 Hz
Approximately, f(1) = 1700 Hz
f(3) = 3 * [350/(4*0.052)]
f(3) = 5048 Hz
Approximately, f(3) = 5100 Hz
