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Andrews [41]
3 years ago
5

The shaft of radius c is subjected to a distributed torque t, measured as torque/unit length of shaft. Shaft A B of length L, fi

xed at B, with x measured from B. Torque t = t sub 0 [1 + (x over L) squared], from t sub 0 at B to 2 t sub 0 at A. The shear modulus is G. Part A Determine the angle of twist at end A. Express your answer as an expression in terms of the variables t0, L, c, and G and any necessary constants.

Physics
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

Angle of twist;Φ = (to•L²)/Gπc⁴

Explanation:

I have attached the explanation.

However, I used D for radius of shaft against c used in the question. So, if we replace the D with c, we'll have;

Φ = (to•L²)/Gπc⁴

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The normal force acting on the object is 500 N in the upward direction

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So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.

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