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Sergio039 [100]
3 years ago
12

What is the acceleration of a proton moving with a speed of 7.0 m/s at right angles to a magnetic field of 1.7 t ?

Physics
1 answer:
Ivenika [448]3 years ago
8 0
We know that a charge moving in a magnetic field is subject to the force:
F = q · v · B

But we also know that:
F = m · a

Therefore, it must be:
m · a = <span>q · v · B

And solving for a:
</span>a = <span>q · v · B / m

Recall that for a proton:
q = 1.6</span>×10⁻¹⁹ C
m = 1.673×10⁻²⁷ kg

Now, you can find:
a = 1.6×10⁻¹⁹ · 7.0 · 1.7 / <span>1.673×10⁻²⁷
   = 1.14</span>×10⁹ m/s²

Hence, the acceleration of the proton is 1.14<span>×10⁹ m/s²</span>.
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