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telo118 [61]
4 years ago
10

True or false The Earth revolves around the sun in a nearly circular orbit.

Physics
2 answers:
Allisa [31]4 years ago
8 0
Well, see, there you go ... using a word that means different things
to different people, and may even mean different things to the same
people at different times.

What does "nearly" mean ? ?  And how do you measure how far
or near to a circle it is ? ?

Every closed gravitational orbit is an ellipse.  An ellipse looks like a
circle that either has or hasn't been squashed.  If it's perfectly round
and hasn't been squashed at all, then we call it a circle.  If it's been
squashed at all, then we call it an ellipse. 

To come up with a number that tells how squashed it is, we divide
               (the distance from the center to one focus of the ellipse)
         by
               (the distance from the center to one vertex of the ellipse). 

The eccentricity of a circle is zero.  When you squeeze the circle,
the more you squash it, the higher the eccentricity gets, until ... if
you totally squash it down to a straight line ... the eccentricity is 1.

Perfect circle . . . . . . zero
Totally squashed . . . 1.00

Orbit            Eccentricity    Compared to Earth

Mercury              0.21               x  12.3
Venus                 0.007             x    0.4
Earth                   0.017             x   1.0
Moon                  0.055             x    3.3
Mars                   0.094             x    5.6
Pluto                   0.244             x 14.6
Halley's Comet  0.97               x  57.1


Conclusions:

-- All of the planets (and their moons too) have nearly circular orbits.

-- While Pluto was considered a planet, it had the most eccentric orbit
of all.  (That's one of the reasons it lost its standing as a planet.  There
were other reasons.)

-- Now the planet with most eccentric orbit is Mercury.  The orbits didn't
change.  Pluto just got bumped from the list.

-- Most comets have very eccentric, far-from-circlular, elliptical orbits.
They go waaaay out, and come waaay in close to the Sun.

Andru [333]4 years ago
3 0

To answer the question.. it is True

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8 0
3 years ago
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A cow is given a growth hormone and then compared to another cow that was not given a growth hormone. Both cows were weighed at
igomit [66]

The complete question is as follows:

A cow is given a growth hormone  and then compared to another cow that  was not given a growth hormone. Both  cows were weighed at 2 years. What is the independent variable?

if the cow is given growth hormone or not  

weight of the cow

same cows  

type of growth hormone

Answer:

The correct answer is - if the cow is given growth hormone or no

Explanation:

The independent variable is here is if the growth hormone is given or not as the variable which is subject to change or manipulated during an investigation and affects the dependent variable is known as the independent variable.

Due to this independent variable manipulation the weight of the cows might be different which makes the weights as the dependent variable.

7 0
3 years ago
A car is initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at
Aleks04 [339]
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
                     = 37.5 m/s
velocity initial = 35 km/hr x  1hr /3600 s x 1000 m/1 km
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a) acceleration = 2.646 m/s^2
b) acceleration in g units  = (2.646m/s^2)/(9.8m/s^2)
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6 0
4 years ago
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MA_775_DIABLO [31]

Answer:

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Explanation:

3 0
3 years ago
A 1.83 kg1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.52
almond37 [142]

Answer:

9.4 N

Explanation:

m = mass of the book = 1.83 kg

\mu _{s} = Coefficient of static friction = 0.522

\mu _{k} = Coefficient of kinetic friction = 0.283

f_{s} = Static frictional force

F = force needed to make the book move

force needed to make the book move is same as the magnitude of maximum static frictional force applied by the desk on the book

Static frictional force is given as

f_{s} = \mu _{s} mg

Hence, the force need to move the book is given as

F = f_{s} = \mu _{s} mg

F = \mu _{s} mg

F = (0.522) (1.83 x 9.8)

F = 9.4 N

4 0
3 years ago
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