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3 years ago

6

As you drive away from a radio transmitter, the radio signal you receive from the station is shifted to longer wavelengths.True

/ False.

1 answer:

Eddi Din [679]3 years ago

5 0

Answer:

True

Explanation:

The radio transmitter generates the radio frequency

As you move away from the radio transmitter, the radio frequency decreases

The relationship between frequency and wavelength is inverse

As the frequency decreases the wavelength of the radio signal increases

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The following number - 0.050437 - written to TWO significant figures would be

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Answer:

0.050000

Explanation:

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3 years ago

1. Compared to sadness, depression:

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Now Abel and Kato use what they learned to answer the following problem. The initial speed of a tennis ball is 54 m/s and the la

34kurt

Answer:

h=19.4m

R=199.07 m

Explanation:

To solve this problem we use the parabolic motion equations:

We define:

$v_{i}$ total initial speed =54 $\frac{m}{s}$

$\alpha$ =angle that forms the total initial speed with the horizontal line= 21°

$v_{ix}$ :initial speed component in horizontal direction

= $v_{i} cos\alpha$ =54*cos 21= 50.41 m/s

$v_{iy}$ :initial speed component in vertical direction

= $v_{i} sin\alpha$ =54*sin21=19.35 m/s

$v_{x}$ :horizontal speed at any point on the parabolic path

$v_{y}$ : vertical speed at any point on the parabolic path

g= acceleration of gravity= 9,8 $\frac{m}{s^{2} }$

Equation of the speed of the football in the vertical direction :

$(v_{y} )^{2} =(v_{yi} )^{2} -2*g*y$ Equation (1)

Calculation of the maximum height(h)

The speed of the ball (vy) in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.

We replace y=h, $v_{y} =0$ , $v_{iy} = 19.39\frac{m}{s}$ , $g=9.8\frac{m}{s^{2} }$ in the equation(1)

$0=19.35^{2} -2*9.8*h$

$h=\frac{19.35^{2} }{2*9.8}$

h=19.1 m

Calculating of the range (R)

Fórmula: $R=v_{ix} *t (m)$ Equation (2)

R is the maximum horizontal distance the ball reaches.

The time (t) for the ball to reach R is twice the time the ball spends to reach the maximum height. Then, we calculate the time $(t_{h} )$ ) when the ball reaches the maximum height

We apply the following equation to calculate $t_{h}$ :

$v_{y} =v_{iy} -g*t_{h}$

$0=19.35-9.8*t_{h}$

$9.8*t_{h} =19.35$

$t_{h} =\frac{19.35}{9.8}$

$t_{h} =1.97 s$

$t=2*t_{h}$

$t=3.95 s$

We replace $v_{ix} =50.41 \frac{m}{s}$ and $t=3.95\frac{m}{s}$ in the equation (2)

R=50.41*3.95

R=199.07 m

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3 years ago

If thomson's model of the atom is correct, what would rutherford have seen in his experiments

gayaneshka [121]

If Thomson's atomic model was correct then it means the atom must be a positively charged sphere and electrons are randomly distributed in it.

Now in Rutherford's experiment we can see that he bombarded alpha particles towards the nuclei of an atom and then he observed the path of the alpha particles

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So in that case none of the alpha particle will move out undeviating in it's initial path

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