Explanation:
(Ques- A) Why does the first method for determining volume work only for a regular-shaped object?
<u>(Ans- A)</u> <em>Because the method requires precise dimensions of objects for result, which is not possible for irregular shaped objects.</em>
(Ques - B) Will the second method for determining volume work for any object or just an odd-shaped one? Why?
<u>(Ans-B)</u> <em>It will work for both regular and irregular shaped objects since both displace equal volumes of water.</em>
(Ques - C) Is one method of measurement more accurate than the other? Why or why not?
<u>(Ans-C)</u> <em>Both are pretty accurate, with some experimental errors which may creep in accidentally. </em>
(Ques- D) Would the displacement method of measurement work for a cube of sugar? What about a cork? Why?
<u>(Ans - D)</u> <em>No, the method would not work because sugar being soluble, will dissolve in water. </em>
<em>No, the method would not work because sugar being soluble, will dissolve in water. Cork is less dense than water so floats on it, with only part of it submerged in water, resulting in displacement of less volume of water than actual volume of Cork.</em>
(Ques-E) What did you find out from this investigation? Be thoughtful in your answer.
<u>(Ans- E)</u> <em>I learnt about determining volume of different objects from this investigation. </em>(Sorry, I know its not a very thoughtful answer)
Answer:
K = 4.07x10⁻³
Explanation:
Based on the reaction:
NH₄I(s) ⇄ NH₃(g) + HI(g)
You can define K of equilibrium as the ratio of concentrations of reactants and products, thus:
K = [NH₃] [HI] / [NH₄I]
But, as NH₄I is a solid, is not taken into account in the equilibrium, that means K expression is:
K = [NH₃] [HI]
As the concentrations in equilibrium of the gases is:
[NH₃] = 4.34x10⁻²M
[HI] = 9.39x10⁻²M
Equilibrium constant, K, is:
K = 4.34x10⁻²M * 9.39x10⁻²M
<h3>K = 4.07x10⁻³</h3>
<u>Answer:</u> The internal energy change for the reaction is -2850 J
<u>Explanation:</u>
- <u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
- <u>Sign convention of work:</u>
Work done for expansion process is taken as negative and work done for compression is taken as positive.
According to the First law of thermodynamics,
where,
= internal energy
q = heat absorbed or released = -2290 J
w = work done = -560 J
Putting values in above equation, we get:
Hence, the internal energy change for the reaction is -2850 J
Number of significant digits is 3.
