Not 100% sure, but I'd have to say this:
When rounding for sig figs, you look at the other numbers in your calculation and see which one has the least amount of sig figs. This number is 2.70. (3 sig figs). So, you round to 3 significant figures in your calculation.
Hope this helped!
Answer:
374 atoms would be present in 22 units of aluminum sulfate.
Explanation:
Formula for Aluminium Sulfate : Al₂(SO₄)₃
Al = 2
S = 1
O = 4
(SO) = 3
∴ Number of atom in one unit is : 2 + (1+4)3 ==> 17
If there are 17 atoms in one unit, therefore;
Number of atoms in 22 units = 17 x 22
= 374 atoms
A-Aluminium sulphate.
B-Calcium Chloride.
C-Potassium sulphate.
D-Potassium Nitrate .
E-Calcium Carbonate.
Answer:
1 g
Explanation:
Given data:
Volume of solution = 250 mL (250 mL × 1 L/1000 mL = 0.25 L)
Molarity of solution = 0.1 M
Amount of sodium hydroxide = ?
Solution:
Molarity = number of moles / volume in L
0.1 M = number of moles /0.25 L
Number of moles = 0.1 M × 0.25 L
M = mol/ L
Number of moles = 0.025 mol
Mass of sodium hydroxide:
Mass = number of moles × molar mass
Mass = 0.025 mol ×40 g/mol
Mass = 1 g
