Answer:
  R = 0.064 dm³ atm K⁻¹ mol⁻¹
Explanation:
Answer:
Explanation:
Data Given:
volume of gas V = 8.8 dm³ 
no. of mole of gas (n) = 1 mole 
Pressure P = 259,392.00 Pa  
Convert Pascal (Pa) to atm (atmospheric pressure)
As 
101,325 Pascals = 1 atm
So, 
259,392.00 Pa  = 2 atm
Then Pressure (P) = 2 atm
Temperature T = 2.00 °C  
change the temperature from °C to K
As  to convert °C to K the below formula used
                    0°C + 273.15 = 273.15K
So, for 2 °C
                     2°C  + 273.15 =  275.15 K
So, 
Temperature T  = 275.15 K
ideal gas constant = ? 
formula used for Ideal gases
                             PV = nRT
as we have to find R of the gas:
we will rearrange the ideal gas equation as below:
R = PV / nT ........................................... (1)
Put value in equation (1)
                   R = 2atm x 8.8 dm³ / 1 mole x 275.15 K
                   R = 17.6 atm. dm³ / 275.15 mol. K
                   R = 0.064 dm³ atm K⁻¹ mol⁻¹
So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹
and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹