Which of the following is the best definition of a scientific theory?
1 answer:
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Answer:
Explanation:
The air 9% mole% methane have an average molecular weight of:
9%×16,04g/mol + 91%×29g/mol = 27,8g/mol
And a flow of 700000g/h÷27,8g/mol = 25180 mol/h
In the reactor where methane solution and air are mixed:
In = Out
Air balance:
91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)
Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>
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The air in the product gas is
95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>
43058 mol air×29g/mol <em>1249 kg air</em>
Percent of oxygen is: =<em>0,231 kg O₂/ kg air</em>
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I hope it helps!
Answer:
The answer to your question is the letter B
Explanation:
I will draw the skeletal structures of these compounds to determine which alcohol is secondary.
Secondary alcohol is alcohol in which the hydroxyl group is attached to a secondary alcohol.
Letter A has primary and secondary alcohol so I discard this choice.
Letter B has secondary alcohol, so this is the correct choice.
The letter C has a primary and 2 secondary alcohols so I discard this choice.
<u>Answer:</u> The specific heat of calorimeter is 30.68 J/g°C
<u>Explanation:</u>
When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of hot water = 46.7 g
= mass of cold water = 45.33 g
= final temperature = 59.4°C
= initial temperature of hot water = 80.6°C
= initial temperature of cold water = 40.6°C
= specific heat of hot water = 4.184 J/g°C
= specific heat of cold water = 4.184 J/g°C
= specific heat of calorimeter = ? J/g°C
Putting values in equation 1, we get:
Hence, the specific heat of calorimeter is 30.68 J/g°C