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1 year ago

(a) Which region of Earth’s crust is not involved in the phosphorus cycle?

1 answer:

3 0

Both abiotic and biotic components of the Earth's system, particularly the biosphere, hydrosphere, and geosphere, phosphorus. Phosphorus cycle cannot be found in the gaseous state in air, in contrast to the compounds of other matter cycles.

This is due to the fact that phosphorus is typically liquid at standard pressures and temperatures. It mostly cycles through sediments, water, and soil. Phosphorus is primarily present in the environment as very minute dust particles. Phosphorous can also be delivered by water or wind in the form of phosphate (both abiotic). Living plants absorb phosphorus, and these plants can either die and be degraded by other living species or they can die and be consumed by other living organisms.

Learn more about Phosphorus here-

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Which statement about silver Ag metal is least reliable

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How many moles of H2S are produced?

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2 years ago

Which of the following is a reasonable ground-state electron configuration?

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2 years ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has $SP^{2}$ O has $SP^{2}$ .

Explanation : The orbitals of oxygen and carbon which are involved in $SP^{2}$ hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and O also has π orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O $SP^{3}$ H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen $SP^{3}$ hydrogen atoms in it. It has $SP^{3}$ hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c: C is $SP^{3}$ O is also $SP^{3}$

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of $SP^{3}$ hybridized bonds.

Answer 5) Bond d: C atom has $SP^{3}$ C atom has $SP^{3}$

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be $SP^{3}$ . Therefore, the orbitals that undergo $SP^{3}$ hybridization are $SP^{3}$ .

Answer 6) Bond e : C1 containing O $SP^{2}$

C2 is $SP^{3}$

Explanation : The carbon atom which contains oxygen along with a double bond has $SP^{2}$ hybridized orbitals involved in the bonding process; whereas the carbon at C2 has $SP^{3}$ hybridized orbitals involved during the bonding. This is for the 'e' position.

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3 years ago