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kolezko [41]
2 years ago
12

(a) Which region of Earth’s crust is not involved in the phosphorus cycle?

Chemistry
1 answer:
Novay_Z [31]2 years ago
3 0

Both abiotic and biotic components of the Earth's system, particularly the biosphere, hydrosphere, and geosphere,  phosphorus. Phosphorus cycle cannot be found in the gaseous state in air, in contrast to the compounds of other matter cycles.

This is due to the fact that phosphorus is typically liquid at standard pressures and temperatures. It mostly cycles through sediments, water, and soil. Phosphorus is primarily present in the environment as very minute dust particles. Phosphorous can also be delivered by water or wind in the form of phosphate (both abiotic). Living plants absorb phosphorus, and these plants can either die and be degraded by other living species or they can die and be consumed by other living organisms.

Learn more about Phosphorus here-

brainly.com/question/1675241

#SPJ4

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dexar [7]
It is spontaneous at 298 k.
7 0
4 years ago
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A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
Mention 4 products formed formed from destructive distillation of coal
LenaWriter [7]

coal gas, gas carbon, coal tar and ammonia liquor,

5 0
3 years ago
Read 2 more answers
If the sentence is true, write true. If the sentence is false , replace the underlined word to make the sentence true.
ivann1987 [24]

1. False

Elements bond to form compounds.

Consider that compounds are essentially clumped up atoms. Knowing this, we know that atoms don’t separate, but rather combine in order to make compounds.

2. True

3. False

Atoms cam lose or gain electrons to form ionic bonds.

When at atom doesn’t have enough electrons to become stable, it will either give or take electrons from another atom in order to become stable. However, because of the fact that the atoms become oppositely charge, they attract each other, thus forming an ionic bond

-T.B.

3 0
3 years ago
What is equal to the number of particles in 36 grams of carbon-12?
HACTEHA [7]

Answer:

3 moles

Explanation:

To solve this problem we will  use the Avogadro numbers.

The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance.  According to this,

1.008 g of hydrogen = 1 mole =  6.022×10²³  atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 =  2 mole

36 g of C-12 = 3 mole

So 3 moles of C-12 equals to the number of particles in 36 g of C-12.

4 0
3 years ago
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