Answer:
1-ethyl-2-methyl cyclopropane.
Explanation:
- The structure of the molecule will be as shown in the attached image.
- The molecular formula of the compound is C₆H₁₂.
- It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
- The ring consist of 3 C atoms, so its name is cyclo propane.
- We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
- <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>
A form of energy associated with the positive and motion of the object.
Answer:
209.98 g of NaOH
Explanation:
We are given;
- Volume of HCl as 3 L
- Molarity of HCl as 1.75 M
We are required to calculate the mass of NaOH required to completely neutralize the acid given.
First, we write a balanced equation for the reaction between NaOH and HCl
That is;
NaOH + HCl → NaCl + H₂O
Second, we determine the number of moles of HCl
Number of moles = Molarity × Volume
= 1.75 M × 3 L
= 5.25 moles
Third, we use the mole ratio to determine the moles of NaOH
From the reaction,
1 mole of NaOH reacts with 1 mole of HCl
Therefore;
Moles of NaOH = Moles of HCl
= 5.25 moles
Fourth, we determine the mass of NaOH
Molar mass of NaOH = 39.997 g/mol
Mass of NaOH = 5.25 moles × 39.997 g/mol
= 209.98 g
Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl
I think the correct answer from the choices listed above is option A. The three components of air are all <span>classified as pure substances since they are not chemically bonded so they can be separated by certain processes and be present as a pure substance. Hope this answers the question.</span>
Answer:
You can fill 212 balloons.
Explanation:
First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>
- P = 14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 25 °C ⇒ 25 + 273.16 = 298.16 K
141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
Then we <u>calculate the number of moles that can fit in a single balloon</u>:
- 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:
- 12.70 mol / 0.0599 mol = 212.09
So the answer is that you can fill 212 balloons.
