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3 years ago

Help me please !!!

Chemistry

1 answer:

Dovator [93]3 years ago

5 0

Answer:

B)The atoms form a bond with a bond length of 75 pm

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Certain gases in the atmosphere trap heat on Earth.

ValentinkaMS [17]

Answer:

Greenhouse

Explanation:

4 0

3 years ago

What is an Alkanoate?

Vlad1618 [11]

Answer: Alkanoate (plural alkanoates) (organic chemistry) Any salt or ester formed from the reaction of an alkaloic acid and alkaloids

Explanation: I looked in my dictionary and found this. I hope this helped

6 0

3 years ago

a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc

ladessa [460]

Answer:

The molarity of the solution is 1.1 $\frac{moles}{liter}$

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case

number of moles of solute= 0.564 moles
volume= 0.510 L

Replacing:

$molarity=\frac{0.564 moles}{0.510 L}$

Solving:

molarity= 1.1 $\frac{moles}{liter}$

The molarity of the solution is 1.1 $\frac{moles}{liter}$

4 0

3 years ago

Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.

liq [111]

/watch?v=DLzxrzFCyOs

6 0

3 years ago

A mixture of MgBr2 and inert material is analyzed to determine the Mg content. First the mixture is dissolved in water. Then all

Mumz [18]

Answer:

9.24% the percent of Mg in the mixture.

Explanation:

Mass of silver bromide = 1.1739 g

Moles of silver bromide = $\frac{1.1739 g}{188 g/mol}=0.006244 mol$

1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.

Moles of bromine atoms = 0.006244 moles

Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :

$\frac{0.006244 mol}{2}=0.003122 mol$

Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :

$1\times 0.003122 mol=0.003122 mol$ magnesium atom

Mass of 0.003122 moles of magnesium :

0.003122 mol × 24 g/mol = 0.07493 g

Mass of the sample = 0.8107 g

Percentage of magnesium in the sample ;

$=\frac{0.07493 g}{0.8107 g}\times 100=9.24\%$

9.24% the percent of Mg in the mixture.

8 0

3 years ago