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Zanzabum
3 years ago
9

Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how

much heat is given off when 3.0 mol c3h8 are reacted with 10.0 mol o2? 1. 672 kj 2. 6036 kj 3. 2012 kj 4. 4024 kj 5. 1555 kj 6. 7392 kj
Chemistry
1 answer:
Olegator [25]3 years ago
5 0
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )


3 mol                10 mol


C_{3}H_{8} is /excess /reactant

because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

Only 2 mole propane will be burned,

so 

2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off

Correct answer is number 4.



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Answer:

The answer to your question is below

Explanation:

a)

Number of atoms = ?

moles of Fe = 4.75

-Use proportions to solve this problem

                            1 mol of Fe --------------------- 6.023 x 10²³ atoms

                          4.75 moles  ---------------------  x

                            x = (4.75 x 6.023 x 10²³) / 1

                            x = 2.86 x 10²⁴ / 1

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moles of 1.058 moles of H₂O

I think this question is incorrect, maybe you wish to know the number of atoms or grams of H₂O.

c)

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                       1 mol of Fe ------------------ 6.023 x 10²³ atoms

                       0.759 moles ---------------  x

                        x = (0.759 x 6.023 x 10²³) / 1

                        x = 4.57 x 10²³ / 1

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d)

Number of molecules = ?

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                         3.5 moles       ------------------   x

                          x = (3.5 x 6.023 x 10²³) / 1

                          x = 2.11 x 10²⁴ molecules

Number of molecules = 2.11 x 10²⁴                                                                        

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