The red colour is the limiting reactant.
Red-blue colour ball and two white balls attached together are reactants.
Red-blue colour ball and two white and one red colour ball attached to each other are products.
<h3>What is a limiting reagent?</h3>
The reactant that is entirely used up in a reaction is called a limiting reagent.
A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.
A product is a substance that is present at the end of a chemical reaction.
Hence,
The red colour is the limiting reactant.
Red-blue colour ball and two white balls attached together are reactants.
Red-blue colour ball and two white and one red colour ball attached to each other are products.
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Answer:
Green, Blue, Indigo, Violet
Explanation:
According to Einstein's equation of photoelectric effect, the kinetic energy of emitted photoelectron is the difference between the energy of the incident photon and the work function of the metal. The work function of the metal referee to the minimum energy that must be supplied in order to eject an electron from a metal surface. The energy of the incident photon must exceed the work function of the metal.
When we look at the electromagnetic spectrum, only the selected colours have frequency above the threshold frequency as shown by the image attached below.
Explanation:
a ...15 seconds×(3600 seconds hour)
Answer:
D
Explanation:
According to IUPAC nomenclature, a negative polyatomic ion has its name ending in 'ate' or 'ite'
As in carbonate (CO3^2-)
Arsenite (AsO3-)
Answer:
Less
Explanation:
Since [Cu(NH3)4]2+ and [Cu(H2O)6]2+ are Octahedral Complexes the transitions between d-levels explain the majority of the absorbances seen in those chemical compounds. The difference in energy between d-levels is known as ΔOh (ligand-field splitting parameter) and it depends on several factors:
- The nature of the ligand: A spectrochemical series is a list of ligands ordered on ligand strength. With a higher strength the ΔOh will be higher and thus it requires a higher energy light to make the transition.
- The oxidation state of the metal: Higher oxidation states will strength the ΔOh because of the higher electrostatic attraction between the metal and the ligand
A partial spectrochemical series listing of ligands from small Δ to large Δ:
I− < Br− < S2− < Cl− < N3− < F−< NCO− < OH− < C2O42− < H2O < CH3CN < NH3 < NO2− < PPh3 < CN− < CO
Then NH3 makes the ΔOh higher and it requires a higher energy light to make the transition, which means a shorter wavelength.