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natka813 [3]
2 years ago
9

What is the mass number of an ion with 108 electrons, 157 neutrons, and a +1 charge?

Chemistry
2 answers:
Margaret [11]2 years ago
5 0

Answer : The mass number for this element is 266.

Explanation :

Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.

Atomic number is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and number of neutrons.

Number of neutrons = Mass number - Number of protons

As we are given :

Number of electrons in an ion = 108

Number of neutrons in an ion = 157

So, number of protons in an ion = 108

For neutral atom, the number of electrons will be:

Number of electrons = Number of protons in an ion + Charge

Number of electrons = 108 + (+1) = 108 + 1 = 109

Now we have to determine the mass number for this element.

Number of neutrons = Mass number - Number of protons

Mass number = Number of neutrons + Number protons

Mass number = 157 + 109

Mass number = 266

Therefore, the mass number for this element is 266.

aniked [119]2 years ago
3 0
I'm assuming you mean the atomic mass number for an element on the periodic table. So if there are 108electrons and a +1 charge then there are 109 protons in the atom and therefore the atomic mass unit is 109

Hope this helps!
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Answer:

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Explanation:

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2 years ago
Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of
Arisa [49]

<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

where,

\Delta x = uncertainty in position = d = 4.50\times 10^{-5}m

\Delta p = uncertainty in momentum  = m\Delta v

m = mass of oxygen molecule = 5.30\times 10^{-26}kg

h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s

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8 0
3 years ago
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<u>Answer:</u>

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<u>Step-by-step explanation:</u>

We need to find out the number of MgCl_2 moles present in 350 grams of a compound.

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So, one mole of MgCl_2 = 24.305 + (35.453 * 2) = 95.211g

1 Mole in 1 molecule of MgCl_2 = \frac{1}{95.211} = 0.0105

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

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