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3 years ago

1.5.2

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

4 0

The molality of a solution : m = 2 mol/kg

<h3>Further explanation</h3>

Given

6 moles of NaOH

3 kg water

Required

The molality

Solution

Molality shows the number of moles dissolved in every 1000 grams of solvent( 1 kg solvent)

m = n. (1000 / p)

m = Molality

n = number of moles of solute

p = Solvent mass (gram)

Input the value :

m = 6 moles : 3 kg

m = 2 mol/kg

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Can someone please show me how to do problem number 4? Please show work so I can try to understand it. Thanks!

larisa86 [58]

With the given formula, we can calculate the amount of CO₂ using the balance equation but we first need the moles of CH₄

1) to find the moles of CH₄, we need to use the ideal gas formula (PV= nRT). if we solve for n, we solve for the moles of CH₄, and then we can convert to CO₂. Remember that the units put in this formula depending on the R value units. I remember 0.0821 which means pressure (P) has to be in atm, volume (V) in liters, the amount (n) in moles, and temperature (T) in kelvin.

PV= nRT

P= 1.00 atm
V= 32.0 Liters
n= ?
R= 0.0821 atm L/mol K
T= 25 C= 298 K

let plug the values into the formula.

(1.00 x 32.0 L)= n x 0.0821 x 298K

n= (1.00 x 32.0 L )/ (0.0821 x 298)= 1.31 moles CH₄

2) now let's convert the mole of CH₄ to moles to CO₂ using the balance equation

1.31 mol CH₄ (1 mol CO₂/ 1 mol CH₄)= 1.31 mol CO₂

3) Now let's convert from moles to grams using the molar mass of CO₂ (find the mass of each atom in the periodic table and add them)

molar mass CO₂= 12.00 + (2 x 16.0)= 44.0 g/mol

1.31 mol CO₂ ( 44.0 g/ 1 mol)= 57.6 g CO₂

Note: let me know if you any question.

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b) Tetrahedral geometry and

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Explanation:

Representation in attachment.

The overall charge in the both structures are -2. The structure (b) is favored by the resonance structures since the formal charge with in the species are remained.

Therefore, structure (b) is the better representation of sulfate ion.

In sulfate ion, sulfur atom is attached with four different oxygen atoms. According to the VSEPR theory , the sufate ion has tetrahedral geometry.

There is four sigma bonds and zero lone pairs present on the central metal atom.

Hence, the hybridization of the sulfur atom is $sp^{3}$

The s and p orbitals of sulfur invovles hybridization and form sigma bonds.The orbitals of sulfur involves $\pi$ bonding.

Therefore, $\pi$ bonds are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

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