Answer:
6.58×10⁻¹⁸ J
Explanation:
Applying
E = kq²/r.................. Equation 1
Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.
From the question,
Given: r = 3.5×10⁻¹¹ m,
Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²
Substitute these values into equation 1
E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)
E = 6.58×10⁻¹⁸ J
The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.
<h3>What is the spring constant?</h3>
Spring constant is defined as the ratio of force per unit displaced length.
Given data;
Mass of block,m=0.250 k
Amplitude,A = 0.125 m
Velocity,V=3.00 m/
Spring constant,K=?
The formula for the spring constant when the spring is oscillate at the given amplitude A:

Hence, the spring constant, k will be 18 N/m
To learn more about the spring constant, refer:
brainly.com/question/4291098
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They got back in the Lunar Explorer Module
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,

:

First we need to find the net charge flowing at a certain point of the wire in one second,

. Using I=0.92 A and re-arranging the previous equation, we find

Now we know that each electron carries a charge of

, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second: