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3 years ago

Which scientist and atomic model are correctly matched

Physics

1 answer:

Novosadov [1.4K]3 years ago

7 0

Answer:

Rutherford and atomic model are correctly matched.

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A boy and a girl are on a spinning merry-go-round. The boy is at a radial distance of 1.2 m from the central axis; the girl is a

Licemer1 [7]

Answer:

E) True. The girl has a larger tangential acceleration than the boy.

Explanation:

In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.

Angular and linear quantities are related

v = w r

a = α r

the boy's radius is r₁ = 1.2m the girl's radius is r₂ = 1.8m

as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different

v₁ = w 1,2 (boy)

v₂ = w 1.8 (girl)

whereby

v₂> v₁

reviewing the claims we have

a₁ = α 1,2

a₂ = α 1.8

a₂> a₁

A) False. Tangential velocity is different from zero

B) False angular acceleration is the same for both

C) False. It is the opposite, according to the previous analysis

D) False. Angular acceleration is equal

E) True. You agree with the analysis above,

8 0

3 years ago

An Ohmic material is one in which its resistance does not depend on the voltage across it or the current within it. In that case

Alexandra [31]

Voltage

Mark brainliest

6 0

4 years ago

A charged particle is accelerated in a uniform electric field. When its velocity is 2 m/s, its electric potential energy is 100

zavuch27 [327]

Answer:

particle's potential energy = 70J

Explanation:

From conservation of energy; K1 + Ue1 = K2 + Ue2

where K1 and K2 are the kinetic energies at two positions and Ue1 and Uue2 are the electrical potential energies at two positions.

k1 = 10J, Ue1 = 100J

K2 = 40J

substitute into K1 + Ue1 = K2 + Ue2

Ue2 = K1 + Ue1 - K2

= 10 +100 - 40

Ue2 = 70J

7 0

3 years ago

In 1977 off the coast of Australia, the fastest speed by a vessel on the water

fenix001 [56]

Answer: 154.08 m/s

Explanation:

Average acceleration $a_{ave}$ is the variation of velocity $\Delta V$ over a specified period of time $\Delta t$ :

$a_{ave}=\frac{\Delta V}{\Delta t}}$

Where:

$a_{ave}=1.80 m/s^{2}$

$\Delta V=V_{f}-V_{o}$ being $V_{o}=0$ the initial velocity and $V_{f}$ the final velocity

$\Delta t=85.6 s$

Then:

$a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}}$

Since $V_{o}=0$ :

$a_{ave}=\frac{V_{f}}{\Delta t}}$

Finding $V_{f}$ :

$V_{f}=a_{ave} \Delta t$

$V_{f}=(1.80 m/s^{2})(85.6 s)$

Finally:

$V_{f}=154.08 m/s$

8 0

3 years ago

A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w

nexus9112 [7]

Answer:

The average speed of the bus, v = 1.55 m/s

Explanation:

Given that,

Number of blocks traveled by bus towards east = 6

Number of blocks traveled by bus towards north = 8

Length of each block = 100 m

Distance traveled by bus towards east 6 x 100 = 600 m

Distance traveled by bus towards north 8 x 100 = 800 m

The total distance traveled, d = 600 + 800 = 1400

Time taken by the bus to travel is, t = 15 minutes

The velocity is given by the formula

v = d/t m

Substituting the values in the above equation

v = 1400 m /(15 x 60) s

= 1.55 m/s

Hence, the average speed of the bus, v = 1.55 m/s

6 0

3 years ago