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Anna71 [15]
3 years ago
14

Which scientist and atomic model are correctly matched

Physics
1 answer:
Novosadov [1.4K]3 years ago
7 0

Answer:

Rutherford and atomic model are correctly matched.

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At a playground, a child slides down a slide that makes a 42° angle with the horizontal direction. The coefficient of kinetic fr
kumpel [21]

Answer:

a = 5.1\ m/s^2

Explanation:

Given,

The angle of the slide=42^\circ

The mass of the child is= m

coefficient of friction = 0.20

when she slides down now apply Newton's law

ma =mg \sin\theta - f

ma = mg\sin \theta -\mu mg \cos \theta

therefore the acceleration

a=g \sin\theta -\mu gcos\theta

a=g[\sin \theta -\mu \cos \theta]

a=9.8\times [\sin 42^\circ -0.2\times \cos 42^\circ]

a = 5.1\ m/s^2

hence, the magnitude of acceleration during her sliding is equal to  a = 5.1\ m/s^2

4 0
3 years ago
Can a body having zero velocity move with uniform speed? Give an example.
GaryK [48]
Sure. Body can move with uniform speed, and having zero velocity, when velocity becomes zero due to change in direction over time t.

For Example. - An Object is moving with uniform speed in a circular path, then after one complete revolution, it's velocity is zero, but speed still remains uniform 

Hope this helps!
3 0
3 years ago
What is the increase in pressure required to decrease volume of mercury by 0.001%
REY [17]

Answer:

Explanation:

Using Boyles law

Boyle's law states that, the volume of a given gas is inversely proportional to it's pressure, provided that temperature is constant

V ∝ 1 / P

V = k / P

VP = k

Then,

V_1 • P_1 = V_2 • P_2

So, if we want an increase in pressure that will decrease volume of mercury by 0.001%

Then, let initial volume be V_1 = V

New volume is V_2 = 0.001% of V

V_2 = 0.00001•V

Let initial pressure be P_1 = P

So,

Using the equation above

V_1•P_1 = V_2•P_2

V × P = 0.00001•V × P_2

Make P_2 subject of formula by dividing be 0.00001•V

P_2 = V × P / 0.00001 × V

Then,

P_2 = 100000 P

So, the new pressure has to be 10^5 times of the old pressure

Now, using bulk modulus

Bulk modulus of mercury=2.8x10¹⁰N/m²

bulk modulus = P/(-∆V/V)

-∆V = 0.001% of V

-∆V = 0.00001•V

-∆V = 10^-5•V

-∆V/V = 10^-5

Them,

Bulk modulus = P / (-∆V/V)

2.8 × 10^10 = P / 10^-5

P = 2.8 × 10^10 × 10^-5

P = 2.8 × 10^5 N/m²

3 0
3 years ago
A 1.2kg ball rolls forward with an acceleration of 1.11 m/s. What is the net force on the ball
grandymaker [24]

Answer:

1.332 N

Explanation:

Net Force = Mass x Acceleration
1.2 x 1.11 = 1.332 N

I'm so sorry if I'm wrong.

8 0
1 year ago
A skateboarder has an acceleration of −1.9 m/s2. If her initial speed is 6 m/s, how long does it take her to stop?
SSSSS [86.1K]
You said that she's losing 1.9 m/s of her speed every second.

So it'll take

             (6 m/s) / (1.9 m/s²)  =  3.158 seconds  (rounded)

to lose all of her initial speed, and stop.
6 0
3 years ago
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