The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
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Magnetic dipole moment of the bar magnet</h3>
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
where;
- B is magnetic field
- m is dipole moment
- μ is permeability of free space
m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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Answer:
c = 4,444.44
Explanation:
You have the following expression for the acceleration of the projectile:
(1)
s: distance to the ground of the projectile
To find the value of the constant c you use the following formula:
(2)
vo: initial velocity = 0 m/s
v: final speed = 200 m/s
Δs: distance traveled by the projectile = 3m - 1.5m = 1.5m
You replace the expression (1) into the expression (2):
You do the constant c in the last equation, then you replace the values of v, s and Δs:
Answer:
A
Explanation:
Becuse its complete number
A. W
Explanation:
The wave that would be produced by the interaction of the two waves shown in the diagram is wave W.
There is no wave in the diagram W.
This type of interference is known as destructive interference.
- Destructive interference occurs when two waves out of phase comes together.
- In this way, they cancel out each other and are terminated.
- If the two waves are in phase, they will reinforce one another.
- When waves reinforce one another, a constructive interference has occurred.
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Color in soap bubbles brainly.com/question/8733443
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