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expeople1 [14]
3 years ago
5

If all objects have gravitational pulls, why is every object not being constantly accelerated toward every other object?

Physics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

Some object have less gravitational pull than other objects.

Explanation:

lisov135 [29]3 years ago
6 0
The earth always produced the same acceleration on every object. But the gravitational force the earth exerts on the objects is different. Their masses are just as frenzy so the effect we see (acceleration) is the same for each.
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Which of the following statements are true? Select all correct responses. Choose all that apply. Choose all that apply. The tota
Ne4ueva [31]
<h3><u>Answer</u>;</h3>

-The total momentum of an isolated system is constant.

-The total momentum of any number of particles is equal to the vector sum of the momenta of the individual particles.

-The vector sum of forces acting on a particle equals the rate of change of momentum of the particle with respect to time.

<h3><u>Explanation</u>;</h3>
  • Momentum is a vector quantity, and therefore we need to use vector addition when summing together the momenta of the multiple bodies which make up a system.
  • The vector sum of forces acting on a particle is equivalent to the rate of change of momentum of the particle with respect to time. This is according to the Newton's second Law of motion. In mathematical terms, ֿF = d ֿp/dt, that is F= ma.
  • According to the Law of conservation of Momentum, or a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
3 0
3 years ago
When two objects collide their momentum after the collision is explained by what
pashok25 [27]
The statement to every reacting there is, there is a opposite and same reacting. 
hope it helps
8 0
3 years ago
What frequency fapproach is heard by a passenger on a train moving at a speed of 18.0 m/s relative to the ground in a direction
Sergio039 [100]

Answer:

The frequency is 302.05 Hz.

Explanation:

Given that,

Speed = 18.0 m/s

Suppose a train is traveling at 30.0 m/s relative to the ground in still air. The frequency of the note emitted by the train whistle is 262 Hz .

We need to calculate the frequency

Using formula of frequency

f'=f(\dfrac{v+v_{p}}{v-v_{s}})

Where, f = frequency

v = speed of sound

v_{p} = speed of passenger

v_{s} = speed of source

Put the value into the formula

f'=262\times(\dfrac{344+18}{344-30})

f'=302.05\ Hz

Hence, The frequency is 302.05 Hz.

7 0
3 years ago
Can someone please help me with this question? ASAP thank you!
Assoli18 [71]

did you get the answer

8 0
3 years ago
Helpp pls .. Which statement is true about the process shown?
Mandarinka [93]

Answer:

I think its A

Explanation:

6 0
3 years ago
Read 2 more answers
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