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expeople1 [14]
3 years ago
5

If all objects have gravitational pulls, why is every object not being constantly accelerated toward every other object?

Physics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

Some object have less gravitational pull than other objects.

Explanation:

lisov135 [29]3 years ago
6 0
The earth always produced the same acceleration on every object. But the gravitational force the earth exerts on the objects is different. Their masses are just as frenzy so the effect we see (acceleration) is the same for each.
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Svetllana [295]
Researchers found the "cosmic microwave background radiation", which is a heat imprint left over from the big bang.

The redshift of light emitted by most galaxies indicates the universe is expanding.

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3 years ago
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How much energy (in kilojoules) is required to convert 200 mL of diethyl ether at its boiling point from liquid to vapor if its
LiRa [457]

Answer:

55.96kJ

Explanation:

Energy = mass of diethyl ether × enthalpy of vaporization of diethyl ether

Volume (v) = 200mL, density (d) = 0.7138g/mL

Mass = d × v = 0.7138 × 200 = 142.76g

Enthalpy of vaporization of diethyl ether = 29kJ/mol

MW of diethyl ether (C2H5)2O = 74g/mol

Enthalpy in kJ/g = 29kJ/mol ÷ 74g/mol = 0.392kJ/g

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4 0
3 years ago
a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?
Bumek [7]

Answer:

25 miles per hour

Explanation:

4 0
3 years ago
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State newtons second law of motion from the equation f: ma​
ANEK [815]

Answer:

wut goes up must come down i dunno lol

Explanation:

5 0
3 years ago
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
kari74 [83]

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

8 0
3 years ago
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