An object increases its velocity from 20 m/s to 63 m/s in 10 s. What is the acceleration of the object?
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The free fall of the phone is an uniformly accelerated motion toward the ground, with constant acceleration equal to
So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by
And if we substitute t=2.7 s, we find the distance covered:
So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by
And if we substitute t=2.7 s, we find the distance covered: