Answer:
The period of oscillation is 1.33 sec.
Explanation:
Given that,
Mass = 275.0 g
Suppose value of spring constant is 6.2 N/m.
We need to calculate the angular frequency
Using formula of angular frequency

Where, m = mass
k = spring constant
Put the value into the formula


We need to calculate the period of oscillation,
Using formula of time period

Put the value into the formula


Hence, The period of oscillation is 1.33 sec.
Answer:
592.92 x 10³ Pa
Explanation:
Mole of ammonia required = 10 g / 17 =0 .588 moles
We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .
From the relation
PV = nRT
P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )
P = 592.92 x 10³ Pa
The ideal mechanical advantage of the screwdriver is 47
Explanation:
In this problem, the screwdriver acts as a lever.
The Ideal Mechanical Advantage (IMA) of a lever is given by:

where:
is the distance of the point of application of the input force from the fulcrum
is the distance of the output force from the fulcrum
In this problem, we have:
, since the fulcrum is 0.500 cm from the end
(the distance between the fulcrum and the point where are we holding the screwdriver)
Substutiting,

Learn more about levers here:
brainly.com/question/5352966
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