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3 years ago

An object increases its velocity from 20 m/s to 63 m/s in 10 s. What is the acceleration of the object?

Physics

1 answer:

notsponge [240]3 years ago

4 0

Answer:

Relative to the chair your speed is zero. Relative to the sun it is 30 km/s.

Explanation:

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When the spring, with the attached 275.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate the

topjm [15]

Answer:

The period of oscillation is 1.33 sec.

Explanation:

Given that,

Mass = 275.0 g

Suppose value of spring constant is 6.2 N/m.

We need to calculate the angular frequency

Using formula of angular frequency

$\omega=\sqrt{\dfrac{k}{m}}$

Where, m = mass

k = spring constant

Put the value into the formula

$\omega=\sqrt{\dfrac{6.2}{275.0\times10^{-3}}}$

$\omega=4.74\ rad/s$

We need to calculate the period of oscillation,

Using formula of time period

$T=\dfrac{2\pi}{\omega}$

Put the value into the formula

$T=\dfrac{2\pi}{4.74}$

$T=1.33\ sec$

Hence, The period of oscillation is 1.33 sec.

4 0

2 years ago

A small cart travels 20 meters to the right in 10 seconds calculate the velocity

stira [4]

The velocity would be 10

3 0

2 years ago

A 2.5-L tank initially is empty, and we want to fill it with 10 g of ammonia. The ammonia comes from a line with saturated vapor

Alex17521 [72]

Answer:

592.92 x 10³ Pa

Explanation:

Mole of ammonia required = 10 g / 17 =0 .588 moles

We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .

From the relation

PV = nRT

P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )

P = 592.92 x 10³ Pa

3 0

2 years ago

kristine speeds past a parked police car at 32 m/s. The police car starts from rest with a uniform acceleration of 2.5 m/s^2. Ho

Digiron [165]

$32 = 0 \times t + \frac{1}{2} \times 2.5 \times t^{2} \\ 32 = 0 + 1.25 \times t {}^{2} \\ 32 = 1.25t {}^{2} \\ \frac{32}{1.25} = \frac{1.25t {}^{2} }{1.25} \\ t {}^{2} = 25.6 \\ \sqrt{t {}^{2} } = \sqrt{25.6} \\ t = 5.1seconds \\$

7 0

2 years ago

A 24.0 cm long screwdriver is used as a lever to open a can of paint. If the fulcrum is 0.500 cm away from the end of the screwd

ELEN [110]

The ideal mechanical advantage of the screwdriver is 47

Explanation:

In this problem, the screwdriver acts as a lever.

The Ideal Mechanical Advantage (IMA) of a lever is given by:

$IMA=\frac{d_i}{d_o}$

where:

$d_i$ is the distance of the point of application of the input force from the fulcrum

$d_o$ is the distance of the output force from the fulcrum

In this problem, we have:

$d_o = 0.500 cm$ , since the fulcrum is 0.500 cm from the end

$d_i = 24.0 cm - 0.500 cm = 23.5 cm$ (the distance between the fulcrum and the point where are we holding the screwdriver)

Substutiting,

$IMA=\frac{23.50 cm}{0.50 cm}=47$

Learn more about levers here:

brainly.com/question/5352966

#LearnwithBrainly

7 0

2 years ago