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Juliette [100K]
3 years ago
11

Two spaceships that have different masses but rocket engines of identical force are at rest in space. if they fire their rockets

at the same time, which ship will speed up faster
Physics
1 answer:
NISA [10]3 years ago
5 0
Force is calculated F=m×a.
If both ships speed up with the same force, but have a different mass, This means that a also has to be different. If F is the same but ship a has a bigger mass(m) than ship b, then the acceleration(a) of ship b has to be bigger so F of each ship is the same. So the ship with the smaller mass will speed up faster.
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A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?
Bezzdna [24]

Answer:

Explanation: The initial velocity has two component v x  and v y. The initial velocity in direction of y is given.

8 0
2 years ago
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Takes 5 seconds and 2,000 J for a crane to lift a very heavy object. Which of these correctly describes power and energy for thi
strojnjashka [21]

Answer:

D

Explanation

take 5x2000 and J is the unit for power therfore it cant be A and B and C are not 10,000.

8 0
2 years ago
How quickly a leaf grows is proportional how big [ie the surface area] the leaf is. If the area of the leaf grows from 2cm2 to 3
marusya05 [52]

Answer: 9 days

Explanation:

  • Step 1

Let the rate of Leaf growth <em>r</em> be defined as, \frac{Increase  in  area}{time taken} = \frac{A1 - A}{t}

where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.

  • Express the proportional relationship in equation.

Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.

r = kA, where k is the rate constant.

therefore, k = \frac{r}{A}

when A = 2cm^{2}, A1 = 3

so k = \frac{\frac{3 - 2}{3}}{2}

= \frac{1}{3} ÷ 2

= 0.33 ÷ 2

k = 0.167

  • After calculating the rate constant k, we then find the time t when A1 is 5cm^{2}
  • we have r = k × A1 = \frac{A1 - A}{t}

so, 0.167 × 2 = \frac{5 - 2}{t}

0.33 = \frac{3}{t}.

t = 3/0.33

Therefore, t = 9 days.

3 0
3 years ago
You lift a 10-kg box to a height of 1m. How much work do you do on the box when you lift it from the ground? (g= 9.81 m/s2)
Andreyy89

Answer:

98.1 Joule

Explanation:

Solution,

⇒Mass(m)=10kg

⇒Weight(F)=Mg=10×9.81=98.1N

⇒Distance(d)=1m

Now,

Work done=F×d

                  =98.1×1

                  =98.1J

5 0
2 years ago
Two long parallel wires are placed side-by-side on a horizontal table. if the wires carry current in opposite directions,
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\vec F = I (\vec L \times  \vec B)

if currents go in opposite directions, wires repel
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