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d1i1m1o1n [39]
3 years ago
14

Which term refers to a quantity that has both magnitude and direction?

Physics
2 answers:
mezya [45]3 years ago
6 0

Answer:

A vector quantity is a quantity this has both magnitude and direction, so, the answer is C.

just olya [345]3 years ago
5 0

Answer:C

Explanation:

There correct answer Is C, because vector quantities are quantities that has both magnitude and direction

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An airplane flies 2500 miles east in 245 seconds what is the velocity of the plane?
forsale [732]

Speed = (distance) / (time)

Speed = (

Velocity = speed, and its direction

The velocity of the plane is 10.2 miles per second East.

(about 48 times the speed of sound)

8 0
3 years ago
Describe how refraction concentrates wave energy so that some parts of a beach erode more.
Zigmanuir [339]

Refraction is the bending of the waves which is result of the fact that different parts of the wave reach the water with different speeds because of the angle approaching the shore.

<span>The wave refraction disperses the wave energy in quiet water areas and sand is deposited.<span>  </span></span>



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3 years ago
What types of crust are colliding between the North American Plate and the Pacific Plate?
svet-max [94.6K]

Answer: G00gle got you bro

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3 years ago
Given that on Earth, gravity causes an acceleration of 9.8 m/s2, what is an acceleration of 7 g?
zzz [600]

Answer:

68.6 m/s^2

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1 g = 9.8 m/s^2

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7 0
3 years ago
You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica
Pani-rosa [81]

Answer:

Length = 2.92 m

Diameter = 0.11 mm

Explanation:

We have m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A} , where:

l is the length

m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3

We divide the first equation by the second equation to get:

\frac{m}{R} = \frac{d A^2}{\rho}

A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8}   \ m^2

Using this Area, we find the diameter of the wire:

D = \sqrt{\frac{4A}{\pi}}

D = \sqrt{\frac{4 \times 3.8 \times 10^{-8} }{\pi}}

D = 0.00011 \ m = 1.1 \times 10^ {-4} = 0.11 \ mm

To find the length, we multiply the two equations stated initially:

mR = d\rho l^2\\\\l^2 = \frac{mR}{d\rho} \\\l^2 = \frac {1.0 \times 10^{-3} \times 1.3}{8960 \times 1.7\times 10^{-8}}

l^2 = 8.534\\l =   2.92 \ m

8 0
3 years ago
Read 2 more answers
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