The right-hand rule predicts the direction of the force on a positively charged object moving in a gravitational field true fals
1 answer:
You might be interested in
Answer:50.39 m/s,
40.46 m
Explanation:
Given
launch angle
Range=240 m
We know that Range
u=50.39 m/s
(b)maximum height of projectile is given by
H=40.46 m
1)
Answer:
Part 1)
H = 30.6 m
Part 2)
t = 2.5 s
Part 3)
t = 2.5 s
Part 4)
Explanation:
Part 1)
initial speed of the ball upwards
so maximum height of the ball is given by
Part 2)
As we know that final speed will be zero at maximum height
so we will have
Part 3)
Since the time of ascent of ball is same as time of decent of the ball
so here ball will same time to hit the ground back
so here it is given as
t = 2.5 s
Part 4)
since the acceleration due to earth will be same during its return path as well as the time of the motion is also same
so here its final speed will be same as that of initial speed
so we have
2)
Answer:
a = 9.76 m/s/s
Explanation:
As we know that the object is released from rest
so the displacement of the object in vertical direction is given as
3)
Answer:
v = 29.7 m/s
Explanation:
acceleration of the rocket is given as
time taken by the rocket
t = 0.33 min
final speed of the rocket is given as
4)
Answer:
Part 1)
y = 25.95 m
Part 2)
d = 6.72 m
Explanation:
Part 1)
As it took t = 2.3 s to hit the water surface
so here we will have
Part 2)
Distance traveled by it in horizontal direction is given as