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Elena-2011 [213]
3 years ago
12

What causes coastal erosion

Physics
1 answer:
Zielflug [23.3K]3 years ago
5 0

La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.

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A 150 g air-track glider is attached to a spring. The glider is pushed in 8.80 cm and released. A student with a stopwatch finds
Alla [95]

Answer:

2.06 N/m

Explanation:

The system makes 10.0 complete oscillations in 17.0 s. So, the frequency of the system is

f=\frac{10.0}{17.0 s}=0.59 Hz

The angular frequency of the system is given by

\omega = 2\pi f=2\pi (0.59 Hz)=3.71 rad/s

In a simple harmonic motion, the angular frequency is related to the mass and the spring constant by

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Here we know

\omega=3.71 rad/s\\m = 150 g = 0.150 kg

So we can solve the formula to find k:

k=\omega^2 m = (3.71 rad/s)^2 (0.150 kg)=2.06 N/m

5 0
4 years ago
The process of physically separating a single-phase mixture into components if the components have different boiling points is c
kobusy [5.1K]
This process of physically separating a single phase mixture into several components would be termed simple distillation, I believe.

As it is mentioned that one is separating them based on their different boiling points.
6 0
4 years ago
A ball is thrown downward from the top of a building with an initial speed of 25 m/s.
Bumek [7]

Answer:

h = 69.6 m

Explanation:

Data:

  • Vo = 25 m/s
  • t = 2.0 s
  • g = 9.8 m/s²
  • h = ?

Formula:

  • \boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}

Replace and solve:

  • \boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}
  • \boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}
  • \boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}
  • \boxed{\bold{h=50\ m+19.6\ m}}
  • \boxed{\boxed{\bold{h=69.6\ m}}}

The building has a height of <u>69.6 meters.</u>

Greetings.

5 0
3 years ago
Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr
svlad2 [7]

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, \sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2

Surface charge density of second surface, \sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2

The electric field at a point between the two surfaces is given by :

E=\dfrac{\sigma}{2\epsilon_o}

E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}

E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.

6 0
3 years ago
Which statements describe properties of stars?
Ede4ka [16]

Statements 1, 3, and 5 are true.

(A, C, and E)

7 0
3 years ago
Read 2 more answers
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