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insens350 [35]
3 years ago
5

1 2 3 4 5 6 7 8 9 10

Physics
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

B) An asteroid impact

Explanation:

Zarrin [17]3 years ago
3 0

Answer:

answer is an ASTEROID

Explanation:

Iridium is a material that forms at very high temperatures, which is why its presence shows that in the impact zone the temperature rose a lot, so we can imagine that the impact was by a body traveling at high speed, which is consistent with a body that comes from space.

An asteroid is a celestial body of some size that when entering the atmosphere heats up and collides with the Earth, leaving a crater that in general is much larger than the diameter of the object.

A meteorite is a small fraction of an asteroid that has been separated by the pressure of the sun, the attraction of the Earth, Moon or another massive body or a combination of these effects, in general, meteorites are small and when they enter the atmosphere They are consumed by heat and very few reach the surface of the Earth, those that do reach are very small.

Therefore due to the size of the crater and the existence of many dead animals around the body must have been very heavy, so the correct answer is an ASTEROID

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The loudness of a sound is the wave's _______
Burka [1]
Amplitude:)

Hope this help!
5 0
2 years ago
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After a wave passes through a medium, particles in the medium
sertanlavr [38]

Answer:

If a particle is affected by a wave, then the particles are displaced. They move along the direction of the wave. Hence, After a wave passes through a medium, particles in the medium are moved along with the wave.

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2 years ago
What is the density of a substance that has a mass of 453g and a volume of 224mL?
Mrrafil [7]
Density is mass per unit volume. In this case, the unit is g/ml
Mass=453g                              ρ=453g/224ml
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6 0
3 years ago
The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This
erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation

g = \frac{GM}{(d-R_{CM})^2}

Where,

G = Gravitational Universal Constant

d = Distance

M = Mass

R_{CM} = Radius earth center of mass

PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,

g = \frac{GM}{(d-R_{CM})^2}

g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}

g = 3.4*10^{-5}m/s^2

PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

\omega = \frac{2\pi}{T}

At the same time we have that centripetal acceleration is given as

a_c = \omega^2 r

Replacing

a_c = (\frac{2\pi}{T})^2 r

a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)

a_c = 3.34*10^{-5}m/s^2

3 0
3 years ago
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