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3 years ago

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Physics

2 answers:

Mandarinka [93]3 years ago

7 0

Answer:

B) An asteroid impact

Explanation:

Zarrin [17]3 years ago

3 0

Answer:

answer is an ASTEROID

Explanation:

Iridium is a material that forms at very high temperatures, which is why its presence shows that in the impact zone the temperature rose a lot, so we can imagine that the impact was by a body traveling at high speed, which is consistent with a body that comes from space.

An asteroid is a celestial body of some size that when entering the atmosphere heats up and collides with the Earth, leaving a crater that in general is much larger than the diameter of the object.

A meteorite is a small fraction of an asteroid that has been separated by the pressure of the sun, the attraction of the Earth, Moon or another massive body or a combination of these effects, in general, meteorites are small and when they enter the atmosphere They are consumed by heat and very few reach the surface of the Earth, those that do reach are very small.

Therefore due to the size of the crater and the existence of many dead animals around the body must have been very heavy, so the correct answer is an ASTEROID

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3 years ago

A cow wanders 30 m North, turns 22 degrees right of its original path, and wanders another 40 m. Find its total displacement.

scoundrel [369]

Answer:OB=58.3m

Explanation:

So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.

now take the starting point as a origin such that cow moves in x-y co-ordinate axis.

As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.

So the final displacement is the length of cow from the origin that is length OB.

now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]

now displacement of cow= length of OB

= $\sqrt{[37.084]^{2}+[44.984]^{2} }$

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1 year ago

A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction

IrinaVladis [17]

The coefficient of friction between the road and the car's tire is determined as 0.78.

<h3>Acceleration of the car</h3>

The acceleration of the car is calculated as follows;

v² = u² - 2as

0 = u² - 2as

a = u²/2s

where;

u is the initial velocity = 97 km/h = 26.94 m/s

a = (26.94)²/(2 x 47)

a = 7.72 m/s²

<h3>Coefficient of friction</h3>

μ = a/g

μ = (7.72)/9.8

μ = 0.78

Learn more about coefficient of friction here: brainly.com/question/14121363

#SPJ1

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2 years ago

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