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Furkat [3]
3 years ago
9

What is one benefit to lifelong physical activity?How can you measure your level of intensity during a physical activity?

Physics
1 answer:
daser333 [38]3 years ago
5 0
It will lower your Chances of diseases, heart attack, and cholesterol. you can measure your intensity by making sure your body is under a safe amount of stress
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Which roots are better underwater , taprroots or fibrous?
4vir4ik [10]

Answer:

The absorption of water and minerals by taproot is more efficient with the taproot system. Fibrous root absorbs water more efficiently as it reaches deep into the soil. Taproots are capable of withstanding drought.

4 0
3 years ago
Energy transfer by convection is usually restricted to what type of substance?
just olya [345]

the anwser is d) fluids

3 0
4 years ago
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A stationary car with a mass of 1500 kg reaches a velocity of 15 meters per second, 5 seconds after starting. What is the car's
Artyom0805 [142]

Answer:

Let me know if you have questions

4 0
4 years ago
A particle moving along the x-axis has a position given by x = (24t – 2.0t 3 ) m, where t is measured in s. What is the magnitud
Vitek1552 [10]
<h2>The magnitude 24 (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving.</h2>

Explanation:

Given,

A particle moving along the x-axis has a position given by

x=(24t-2.0t^3) m      ........ (1)

To find, the magnitude (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving = ?

Differentiating equation (1) w.r.t, 't', we get

\dfrac{dx}{dt} =\dfrac{d((24t-2.0t^3))}{dt}

⇒ \dfrac{dx}{dt} =24(1)-3(2.0)t^{2} =24-6t^{2}     ....... (2)

⇒ 24-6t^{2} = 0

⇒ t^{2}=2^{2}

⇒ t = 2 s

Again, differentiating equation (2) w.r.t, 't', we get

\dfrac{d^2x}{dt^2} =-12t

Put t = 2, we get

\dfrac{d^2x}{dt^2} =-12(2)=24

Thus, the magnitude 24 (\dfrac{m}{s^2} ) of the acceleration of the particle when the particle is not moving.

3 0
3 years ago
Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
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