Write an equation system based on the problem # The perimeter is 360 yg 2l + 2w = 360 # The length is 20 yd longer than the width l = 20 + w
Solve the equation system, substitute 20+w as l to the first equation to find the value of w 2l + 2w = 360 2(20+w) + 2w = 360 40 + 2w + 2w = 360 4w + 40 = 360 4w = 360 - 40 4w = 320 w = 320/4 w = 80 The width is 80 yd
Find the length by substituting the value of w l = 20 + w l = 20 + 80 l = 100 The length is 100 yd
If P=360, then 360yd / 4 sides = 90yds each side. Now that it is a rectangle, the Length should be more than the width, so if the length is 20yds more than the width, do 90 - 20 two times, Width= [ (90yds - 20yds)*2 ]
To sum things up, Length = 110; Width = 70.| 110*2 = 220, 70 * 2 = 140, 220+140 = 360.
