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mote1985 [20]
3 years ago
7

What are Factor pairs of 21 x squared

Mathematics
2 answers:
Temka [501]3 years ago
5 0
1 * 21 and 3 * 7 are the only factors of 21
You can match these up with the x^2 or have one x with each factor.
x * 21x
3x * 7x
x^2 * 21
1 * 21x^2
3 * 7x^2
3x^2 * 7
Serhud [2]3 years ago
4 0
21x^2

you CAN'T factor 21x^2
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Four more than twice a number is -10
Anna [14]

Answer:

-7

Step-by-step explanation:

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A square base of a pyramid has the dimensions 5 yards by 5 yards. The height of one of the triangular faces is 12 yards. How can
-Dominant- [34]

Answer:

145 yards squared

Step-by-step explanation:

So the area of the base is area of a square with side length of 5 yards 5*5=25

The area of one triangular face base times height divided by two and then simply multiplied by 4 because there are 4 triangular faces.

(\frac{5*12}{2} )*4 = 120

So the total surface area is 25+120=145 yards squared

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Prove x²+y² = (x+y) (x-y)​
gtnhenbr [62]

Answer:

(x+y)(x-y)

x^2 - xy + xy - y^2

x^2 - y^2

7 0
2 years ago
R^3 +4r^2-25r-100<br><br> Help
Marina86 [1]

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

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Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

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7 0
3 years ago
Please help and explain part A B and C
Umnica [9.8K]
Part A you would just distribute your 3 to your X and your 5. After doing that you would get 3x+15+x=4x. Next you would combine like terms, meaning combine your x's together that is on the same side of your equal sign. So you would add 3x and x. When finished with that you would get, 4x+15=4x. You would then subtract your 4x on both sides of your equal sign. You then would get 15=0 which is no solution.

Part B you would distribute your 4 to your 1 and -x. After doing this your equation should then look like 4-4x=5x+8. Next you would try to get your like terms together. You would add 4x on both sides of your equal sign. Your equation should then look like 4=9x+8. Next you would subtract your 8 on both sides of the equal sign because your getting your terms together. Your equation should then look like, -4=9x. This answer would be one solution.

Part C you would combine your like terms, meaning add your 2x and x together to get your equation looking like, 3x+5=5+3x. You can tell just by looking at this equation it's going to be a infinite number of solutions. 

Hope this helps! (:
8 0
3 years ago
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