All categories

3 years ago

If 1 meter = 3.28 feet, what is the height of the Washington Monument in meters?

2 answers:

6 0

Washington Monument=555 ft 1 meter=3.28 feet 555/3.28 = height in meters 169.21 meters tall B. A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket

jasenka [17]3 years ago

5 0

Since you didn't provide how tall the Monument was, I took the liberty to find it and it is 555 feet tall. So to convert to meters we must divide 555 by 3.28 or multiply it by 0.3048 (this is the method I used).
555 x 0.3048 = 169.164 meters

You might be interested in

Calculate the average distances the car and the washer traveled from the top of the track. Record the averages and your qualitat

leva [86]

The distance the car traveled was 75 cm, and the distance the washer traveled was 200 cm. I know this because of coarse I had to calculate the distance and I just took the quiz and it said I got it right.
(I also calculated it again to make sure it was correct before I gave you the answer.)

P.S- Please mark me Brainliest, thank you (^v^).

8 0

3 years ago

Read 3 more answers

A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9

11111nata11111 [884]

Answer:

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

$m_{1} v_{1}=m_{2} v_{2}$

$\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }$

$\mathrm{v}_{1} \text { velocity before the collision }$

$\mathrm{v}_{2} \text { velocity after the collision }$

$\mathrm{m}_{1}=600 \mathrm{kg}$

$\mathrm{m}_{2}=900 \mathrm{kg}$

$\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}$

$600 \times 5=900 \times v_{2}$

$3000=900 \times v_{2}$

$\mathrm{v}_{2}=\frac{3000}{900}$

$\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}$

$\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}$

5 0

3 years ago

Why do areas north of the artic circle in tje northern hemisphere experience a polar day lasting for several months during summe

adell [148]

The regioin is titled towqrd the Sun during polar day. (C)

(The same exact thing happens in areas south of the Antarctic Circle
in the southern hemisphere. The only difference is that the whole thing
is spelled better in the South.)

7 0

3 years ago

Read 2 more answers

If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray i

iVinArrow [24]

If light travels from oil to water at an angle, what happens to the direction of the light ray in water with respect to the normal, is it moves away from the normal.

7 0

3 years ago

A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rid

yanalaym [24]

11.0 second hope i helped

6 0

3 years ago