Answer:
mechanical
Explanation:
the energy is carried by water <3 hope this helped
Answer:
The lenses with different focal length are four.
Explanation:
Given that,
Radius of curvature R₁= 4
Radius of curvature R₂ = 8
We know ,
Refractive index of glass = 1.6
When, R₁= 4, R₂ = 8
We need to calculate the focal length of the lens
Using formula of focal length
![\dfrac{1}{f}=(n-1)(\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%28n-1%29%28%5Cdfrac%7B1%7D%7BR_%7B1%7D%7D%2B%5Cdfrac%7B1%7D%7BR_%7B2%7D%7D%29)
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}+\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B4%7D%2B%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=\dfrac{9}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%5Cdfrac%7B9%7D%7B40%7D)
![f=4.44\ cm](https://tex.z-dn.net/?f=f%3D4.44%5C%20cm)
When , R₁= -4, R₂ = 8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}+\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B-4%7D%2B%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=-\dfrac{3}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D-%5Cdfrac%7B3%7D%7B40%7D)
![f=-13.33\ cm](https://tex.z-dn.net/?f=f%3D-13.33%5C%20cm)
When , R₁= 4, R₂ = -8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}-\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B4%7D-%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=\dfrac{3}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%5Cdfrac%7B3%7D%7B40%7D)
![f=13.33\ cm](https://tex.z-dn.net/?f=f%3D13.33%5C%20cm)
When , R₁= -4, R₂ = -8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}-\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B-4%7D-%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=-\dfrac{9}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D-%5Cdfrac%7B9%7D%7B40%7D)
![f=-4.44\ cm](https://tex.z-dn.net/?f=f%3D-4.44%5C%20cm)
Hence, The lenses with different focal length are four.
The area of the Earth (Ae) that is irradiated by is given by:
Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2
On the Earth, insolation (We) = Psun/Ae
Therefore,
Psun (Rate at which sun emits energy) = We*Ae = 1.4*2.827*10^23 = 3.958*10^23 kW = 3.958*10^26 W
Answer:
181.48 N
Explanation:
Calculate the area :
Area = pi * r² ;
pi = 3.14 ; r1 = 90cm /100 = 0.9m ; r2 = 10/100 = 0.1m
Area 1, A1 = 3.14 * 0.1² = 0.0314 m²
Area 2, A2 = 3.14 * 0.9² = 2.5434 m²
Force, F = mass * acceleration due to gravity
F2 = 1500 * 9.8 = 14700 N
Force 1 / Area 1 = Force 2 / Area 2
Force 1 = (Force 2 / Area 2), * Area 1
Force 1 = (14700 / 2.5434) * 0.0314
Force = 5779.6650 * 0.0314
= 181.48 N