1.
Area of shaded region,
=(Area of bigger circle) - (Area of smaller circle)
=πR^2 - πr^2
=π ( R^2 - r^2 )
=3.14 ( 8^2 - 4^2)
=3.14 × ( 64 - 16 )
=3.14 × 48
=150.72 cm^2
2.
Area of shaded region,
=(Area of big semi-circle) - ( Area of small semi-circle)
=(πR^2)/2 - (πr^2)/2
=π/2 ( R^2 - r^2 )
=3.14/2 ( 6^2 - 3^2 )
=1.57 × ( 36 - 9 )
=1.57 × 27
=42.39 cm^2
HOPE THIS WILL HELP YOU
The independent variable would be the fixed rate of $3 because the amount for each mile driven changes based on how far they drive
Answer:
B
Step-by-step explanation: its b
Answer:
The normal distribution is explained for the solution of this question.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean = 25, Standard Deviation = 3.8
This means that
So
If P(X > k) = a
We have to find when Z has a pvalue of 1 - a.
If P(X < k) = a
We have to find when Z has a pvalue of a.
Answer:
C
Step-by-step explanation:
There is absolutely no correlation between class size and number of absences.