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Answer:
Angle of diffraction for second order maxima is θ = 18.941°
Explanation:
From the question it is given that
wavelength of incident light = λ = 541 nm = 541 x
order of maxima = n =2
diffraction grating has 600 lines per mm
⇒ distance between two slit is = 1.66 x
m
using the relation of Braggs diffraction formula i.e.,
2dsinθ = nλ ..................................(1)
where, d = distance between two lines of grating
θ is the angle of diffraction
n= order of maxima
λ is the intensity of incident photon
on substituting the respected values in relation (1) we get,
2 x 1.66 x m sinθ = 2 x 541 x
⇒ sinθ = 0.3246
⇒ θ = = 18.941 °
(a)
The change in potential energy of the electron is given by:
where
is the magnitude of the electron's charge
is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find
(b) 78 kV
The potential difference the electron has moved through is given by
where
is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find