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kenny6666 [7]
3 years ago
12

Why is it difficult to convert miles to yards

Physics
2 answers:
shepuryov [24]3 years ago
6 0

There's really no "why", because it's not difficult at all.
 
Simply multiply the number of miles by 1,760, and bada boom,
there you have the same distance described in yards.

Lelechka [254]3 years ago
3 0
In today's technological age it would be immensely easy to make such a conversion. There are countless tools on the internet that can do the job for you incredibly quickly and easily. Nevertheless, I'll give you an idea about how it could be done.

1\quad mile\quad =\quad 1760\quad yards\\ \\ \frac { 1 }{ 1760 } \quad \times \quad 1\quad mile\quad =\quad 1760\quad \times \quad \frac { 1 }{ 1760 } \quad yards\\ \\ \frac { 1 }{ 1760 } \quad miles\quad =\quad 1\quad yard
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How did harlow shapley conclude that the sun was not in the center of the milky way galaxy?
timurjin [86]

We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.

<h3>What is the work of Harlow Shapley?</h3>

Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.

There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.

Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.

To learn more about Harlow Shapley's original estimate go to - brainly.com/question/28145909

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3 0
2 years ago
If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa
vladimir2022 [97]

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

◆ E = 100N

This is a Right answer...

I hope you understand...

7 0
3 years ago
Why does a plastic comb attract small bits of paper after rubbing with wool?
navik [9.2K]
Static electricity. Like the balloon against hair
5 0
3 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
How are physical descriptions and physical properties similar
elena55 [62]

They are both used to observe and describe matter.

5 0
3 years ago
Read 2 more answers
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