Answer:
Explanation:
It is frictional force of the ground that helps in bringing the vehicle to stop . In the process of stopping , negative work is done on the car by friction force to overcome its kinetic energy .
At levelled road , for stoppage
Kinetic energy of vehicle = Work done by frictional force . = friction force x displacement .
At upward slopping road , gravitational force acting downward also helps the vehicle to stop do friction has to do less work .
At upward inclined road , for stoppage
Kinetic energy of vehicle = Work done by frictional force + work done by gravitational force = (friction force + gravitational force ) x displacement .
Hence displacement is less .
At downward slopping road , friction has to do more work because friction has to do work against gravitational force acting downwards wards and kinetic energy of the vehicle also .
At downward inclined road , for stoppage
Kinetic energy of vehicle + work done by gravitational force = Work done by frictional force = friction force x displacement .
Hence displacement is more .
The car is moving with velocity 1m/s
This is because of conservation of linear momentum.
The mass of the (elevator + person) is (2,000 kg + 60 kg) = 2,060 kg .
The weight is (mass x gravity) = (2,060 x 10) = 20,600 newtons
Work = (force x distance) = (20,600 newtons x 24m) = <em>494,400 joules</em>
The speed, acceleration, and how much time it takes don't make any
difference, unless you want the average power during the lift.
Power = (work)/(time) =
494,000 J / (24/4 m) =
494,000 J / 6 sec = <em><u>82,400 watts</u></em> wow !
Answer:
391.67Hz
Explanation:
The fundamental frequency formula in string is expressed as;
Fo = V/2L
V is the velocity of the wave = 329m/s
L is the length of the string = 42cm = 0.42m
Substitute
Fo = 329/2(0.42)
Fo = 329/0.84
Fo = 391.67Hertz
Hence the fundamental frequency of a mandolin string is 391.67Hz