Ask question

Ask question

All categories

konstantin123 [22]

3 years ago

7

A spherical tank with radius 4 m is half full of a liquid that has a density of 900 kg/m3. The tank has a 1 m spout at the top.

Find the work W required to pump the liquid out of the spout. (Use 9.8 m/s2 for g.)

1 answer:

kompoz [17]3 years ago

7 0

The answer & explanation for this question is given in the attachment below.

You might be interested in

A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the

I am Lyosha [343]

Answer:

If she stands on the North side of a river flowing to the East at 5 mph,

she must head towards the SouthWest to arrive on the South side of the river directly across from her starting point and we have

x^2 + 5^2 = 10^2 where x is her speed directly across the river

x = (75)^1/2 = 8.66 mph towards the South

sin theta = 5 / 10 = 1/2

She must angle the boat at 30 deg from straight South

4 0

1 year ago

The car starts from a room with a constant acceleration of 5 ms-2. What path will it pass in 6 seconds and what speed will it re

Kobotan [32]

Answer: The speed will be 30 m/s .

Explanation:

Given: Initial velocity of the car: u = 0 m/s

Constant Acceleration: a = 5 m/s²

Time: t= 6 seconds

To find: Final velocity(v)

Formula: v = u+at

Substitute values in the formula, we get

v= 0+(5)(6) m/s

⇒ v= 30 m/s

i.e. Final velocity = 30 m/s

Hence, the speed will be 30 m/s .

4 0

2 years ago

Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How

zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

$angle = \frac{1 Parsec}{distance}$

so we have

$distance = \frac{1 Parsec}{angle}$

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

$d_a = \frac{1 Parsec}{1} = 1 Parsec$

distance of star B is given as

$d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec$

So star A is closer than star B

7 0

3 years ago

A 241 kg mass is lifted 1.8 m. What is the potential energy of the mass (in J)?

Korolek [52]

Answer:

mass is lifted 1.8 m. What is the potential energy of the mass 4. A 100 kg

6 0

2 years ago

Read 2 more answers

A person suffering from anaemia gets tired after a short walk

FrozenT [24]

Answer:

yes

Explanation:

you will feel weary after shorter times

5 0

3 years ago

Read 2 more answers