1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
konstantin123 [22]
3 years ago
7

A spherical tank with radius 4 m is half full of a liquid that has a density of 900 kg/m3. The tank has a 1 m spout at the top.

Find the work W required to pump the liquid out of the spout. (Use 9.8 m/s2 for g.)

Physics
1 answer:
kompoz [17]3 years ago
7 0

The answer & explanation for this question is given in the attachment below.

You might be interested in
Compare the gravitational acceleration on the following objects compared to the Sun using:
arsen [322]

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

<h3>Mass of the planets</h3>

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765  x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

<h3>Radius of the planets</h3>

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

<h3>Gravitational acceleration of White dwarf compared to Sun</h3>

\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86

<h3>Gravitational acceleration of Neutron star compared to Sun</h3>

\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}

Learn more about acceleration due to gravity here: brainly.com/question/88039

3 0
2 years ago
Based on the graph, how would you describe the net forces acting on the moving
ladessa [460]

Given the velocity-time graph of an object.

The slope of a velocity-time graph gives the acceleration acting on the object.

From the graph, we can see that the slope of the graph is zero. That is, the velocity of the object is constant and hence the net acceleration acting on the object is zero.

From Newton's second law, the net force acting on an object is given by the product of the mass of the object and its velocity. Therefore when the acceleration of the object is zero, the net force on the object is also zero.

Therefore the net force acting on the given object is zero. Hence, the correct answer is option A.

3 0
1 year ago
Suppose that an object travels from one point in space to another. Make a comparison between the magnitude of the displacement a
Rashid [163]

Answer:

- Distance is a scalar quantity, defined as the total amount of space covered by an object while moving between the final position and the initial position. Therefore, it depends on the path the object has taken: the distance will be minimum if the object has travelled in a straight line, while it will be larger if the object has taken a non-straight path.

- Displacement is a vector quantity, whose magnitude is equal to the distance (measured in a straight line) between the final position and the initial position of the object. Therefore, the displacement does NOT depend on the path taken, but only on the initial and final point of the motion.

If the object has travelled in a straight path, then the displacement is equal to the distance. In all other cases, the distance is always larger than the displacement.

A particular case is when an object travel in a circular motion. Assuming the object completes one full circle, we have:

- The distance is the circumference of the circle

- The displacement is zero, because the final point corresponds to the initial point

3 0
3 years ago
If you travel 5 miles north then turn and travel 5 miles south, you are now _____ miles from where you started.
horsena [70]
0 miles from where you started
3 0
3 years ago
Read 2 more answers
Which two things determine an object’s momentum?
son4ous [18]

Momentum (in terms of classical mechanics) is defined as p = m*v, where m is the mass and v is the velocity.

6 0
2 years ago
Read 2 more answers
Other questions:
  • assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e
    12·1 answer
  • Can someone explain to me #4.
    8·1 answer
  • One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i
    9·1 answer
  • for any object suspended by any number of ropes, wires, or chains, how is the total amount of tension (tension in each rope adde
    6·1 answer
  • Now that you are familiar with MRI's, nanotechnology and micro-bots, use your imagination to brainstorm other probable invention
    9·1 answer
  • In nuclear reactions, the products have less than the reactants. A) mass B) energy C) momentum D) mass-energy​
    9·1 answer
  • Sian wants to measure the number of seconds that it takes for the contents of a beaker to change from clear to purple. Which of
    10·2 answers
  • Calculate net force <br> 532N 215N
    9·1 answer
  • If a ball is thrown straight up into the air, what is its acceleration as it moves upward? What is its acceleration when it reac
    7·2 answers
  • .................... ​
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!