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victus00 [196]
3 years ago
10

A periodic wave has a fixed pattern that is repeated. What is one completion of the wave pattern called?

Physics
1 answer:
Kaylis [27]3 years ago
7 0
It is called cycle. Letter D
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A 720 g softball is traveling at 15.0 m/s when caught. If the force of the glove on the ball is 520 N, what is the time it takes
Sholpan [36]

Answer:

The time it takes the ball to stop is 0.021 s.

Explanation:

Given;

mass of the softball, m = 720 g = 0.72 kg

velocity of the ball, v = 15.0 m/s

applied force, F = 520 N

Apply Newton's second law of motion, to determine the time it takes the ball to stop;

F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.72 \ \times \ 15}{520} \\\\t = 0.021 \ s \\

Therefore, the time it takes the ball to stop is 0.021 s.

5 0
3 years ago
What influences the path that surface currents take?
Anastasy [175]
The answer is wind forces and Earth’s rotation
8 0
3 years ago
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What happens to energy and frequency of a wave if its wavelength increases?
Dahasolnce [82]

Answer:

Waves can be measured using wavelength and frequency. ... The distance from one crest to the next is called a wavelength (λ). The number of complete wavelengths in a given unit of time is called frequency (f). As a wavelength increases in size, its frequency and energy (E) decrease.

7 0
2 years ago
A car with a mass of 2200 kg is travelling at a rate of 55 m's. What is the cars momentum? *
Varvara68 [4.7K]
  • Mass=2200kg
  • Velocity=55m/s

\\ \sf\bull\dashrightarrow Momentum=Mass\times Velocity

\\ \sf\bull\dashrightarrow Momentum=2200(55)

\\ \sf\bull\dashrightarrow Momentum=121000kgm/s

7 0
2 years ago
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If a soap bubble is 115 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated
sp2606 [1]

Answer:

611.8 nm

Explanation:

n_{oil} = Index of refraction of soap bubble  = 1.33

t = thickness of the soap bubble = 115 nm = 115 x 10⁻⁹ m

\lambda = wavelength of light = ?

m = order = 0

For reflection , the necessary condition is

2 n_{oil} t = (m + 0.5) \lambda

2 (1.33)(115\times 10^{-9})= (0 + 0.5) \lambda

\lambda = 6.118\times 10^{-7}

\lambda = 611.8 nm

7 0
2 years ago
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